The proportion of time per day that all checkout counters in a supermarket are busy is a random variable Y with a density func given by Scy²(1 – y)5, 0 sys 1, f(y) = · elsewhere.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.1: Measures Of Center
Problem 9PPS
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The proportion of time per day that all checkout counters in a supermarket are busy is a random variable Y with a density function
given by
|cy²(1 – y)5, 0 <ys 1,
f(y) :
elsewhere.
(a) Find the value of c that makes f(y) a probability density function.
C = 0.01190
(b) Find E(Y). (Use what you have learned about the beta-type distribution.)
E(Y)
.1666
(c) Calculate the standard deviation of Y. (Round your answer to four decimal places.)
=
(d) Find P(Y > µ + 20). (Round your answer to four decimal places.)
Transcribed Image Text:The proportion of time per day that all checkout counters in a supermarket are busy is a random variable Y with a density function given by |cy²(1 – y)5, 0 <ys 1, f(y) : elsewhere. (a) Find the value of c that makes f(y) a probability density function. C = 0.01190 (b) Find E(Y). (Use what you have learned about the beta-type distribution.) E(Y) .1666 (c) Calculate the standard deviation of Y. (Round your answer to four decimal places.) = (d) Find P(Y > µ + 20). (Round your answer to four decimal places.)
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