The projection lens in a certain slide projector is a single thin lens. A slide 23.7 mm high is to be projected so that its image fills a screen 1.71 m high. The slide- to-screen distance is 3.02 m.
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A: Solution: Given, focal lengthf = 150 mm = 0.115 mdistance of object = u = 158mm = 0158m
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- Two lenses are mounted d = 39 cm apart on an optical bench. The focal length of the first lens is f1 = 9.8 cm and that of the second lens is f2 = 3.1 cm. An object of height ho = 4.9 cm is placed at a distance of do = 24 cm in front of the first lens. Part (a) Ignoring the second lens for now, at what distance, in centimeters, behind the first lens is the object’s image formed by that lens? di =? Part (b) Calculate the magnification of that image, including its sign. m =? Part (c) Which choice best describes that image? choose the correct answer 1) Real and inverted 2) Virtual and inverted 3) Virtual and upright. 4) Real and upright. 5) None of these. Part (d) Now consider the two-lens system and the final image it forms, i.e., the image created by the second lens. What is the distance, in centimeters, between the object and its final image? D =?A camera with a 70 mm lens takes a photograph of a 2.10 m-tall object located 46 m away. Calculate the height of the image (in mm) on the film. Enter the numerical part of your answer to one decimal figure. Hint: Remember that the sign of the magnification is significant.A 2.4 cm diameter coin (your object) is placed 10 cm in front of a concave lens of focal length 20 cm. Behind the concave lens is a convex lens of focal length 15 cm. The two lenses are 40 cm apart. What is the distance of the image from the coin? What is the magnification?
- A camera is equipped with a lens with a focal length of 40 cm. When an object 1.9 m (190 cm) away is being photographed, what is the magnification?The focal points of a diverging lens are 18.8 cm from the lens. An object is placed 41.8 cm in front of the lens. What is the magnification of the image produced?How far from a lens having a focal length of +150 mm must the object be placed if it is to form a virtual image that is 3.0 times the size of the object?
- When viewed through a magnifying glass, a stamp that is 2.6 cm wide appears upright and 4.9 cm wide. What is the magnification?A camera with a 110 mm lens takes a photograph of a 1.10 m-tall object located 41 m away. Calculate the height of the image (in mm) on the film. Enter the numerical part of your answer to one decimal figure. Hint: Remember that the sign of the magnification is significant.When viewed through a magnifying glass, a stamp that is 2.8 cm wide appears upright and 4.8 cm wide. What is the magnification?
- There is a lens combinations between two converging lenses that have focal lengths of f1=13 cm (lens 1) and f2=16 cm (lens 2). They are separated by 56 cm along a horizontal line. There is a lit candle (height ho) placed 36 cm in front of the lens 1 (f1=13 cm). Thus, the separation between the candler and the second lens (f2=16 cm) is 92 cm (image attached) 1. Please -what is total magnification in thiz arrangmennt?When viewed through a magnifying glass, a stamp that is 1.9 cm wide appears upright and 5.2 cm wide. What is the magnification?Information for image 1 m_a = 4.0000E+9 kg m_m = 2.8000E+8 kg v_ai x = -1100 m/s v_mi x = 2357 m/s v_fx = -8.73841×102 m/s Information for image 2 m_1 = 1.2840E+9 kg m_2 = 2.9960E+9 kg θ_1 = 32.2 degrees θ_2 = 61.5 degrees v_1 = 2.935×103 m/s What is the value of v_2? How much energy was released in the explosion?