The projection lens in a certain slide projector is a single thin lens. A slide 23.7 mm high is to be projected so that its image fills a screen 1.71 m high. The slide- to-screen distance is 3.02 m.
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A: Solution: Given, focal lengthf = 150 mm = 0.115 mdistance of object = u = 158mm = 0158m
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A: Object height =2.3cm Image height=+4.9cm Magnification=image heightObject height=4.9cm2.3cm=2.13
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A: Magnification (m) is given asMagnification (m) = image dimensionobject dimension
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Q: X-? 30 cm 1.5 m
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