The program below uses pointer arithmetic to determine the size of a 'char' variable. By using pointer arithmetic we can find out the value of 'cp' and the value of 'cp+1'. Since cp is a pointer, this addition involves pointer arithmetic: adding one to a pointer makes the pointer point to the next element of the same type. For a pointer to a char, adding 1 really just means adding 1 to the address, but this is only because each char is 1 byte. Compile and run the program and see what it does. Write some code that does pointer arithmetic with a pointer to an int and determine how big an int is. Same idea – figure out how big a double is, by using pointer arithmetic and printing out the value of the pointer before and after adding 1. What should happen if you added 2 to the pointers from exercises 1 through 3, instead of 1? Use your program to verify your answer #include int main( ) { char c = ‘Z’; char *cp = &c; printf("cp is 0x%08x\n", cp); printf("The character at cp is %c\n", *cp); /* Pointer arithmetic - see what cp+1 is */ cp = cp+1; printf("cp is 0x%08x\n", cp); /* Do not print *cp, because it points to memory not allocated to your program */ return 0; }
The
variable. By using pointer arithmetic we can find out the value of 'cp' and
the value of 'cp+1'. Since cp is a pointer, this addition involves pointer
arithmetic: adding one to a pointer makes the pointer point to the next
element of the same type.
For a pointer to a char, adding 1 really just means adding 1 to the address,
but this is only because each char is 1 byte.
Compile and run the program and see what it does. Write some code that does pointer arithmetic with a pointer to an
int and determine how big an int is.
Same idea – figure out how big a double is, by using pointer
arithmetic and printing out the value of the pointer before and
after adding 1.
What should happen if you added 2 to the pointers from exercises
1 through 3, instead of 1? Use your program to verify your
answer
#include <stdio.h>
int main( )
{
char c = ‘Z’;
char *cp = &c;
printf("cp is 0x%08x\n", cp);
printf("The character at cp is %c\n", *cp);
/* Pointer arithmetic - see what cp+1 is */
cp = cp+1;
printf("cp is 0x%08x\n", cp);
/* Do not print *cp, because it points to
memory not allocated to your program */
return 0;
}
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