**Question 1:**The program below reads two integers \( n \) and \( m \) from the user. Assume the user enters non-negative values for both. In terms of \( n \) and \( m \), select the correct formula for the total value printed at the end of the program.```c#include int main() { int n, m; int i, j, total; printf("enter n (NON_NEGATIVE): "); scanf("%d", &n); // assume user enters a valid integer >= 0 printf("enter m (NON_NEGATIVE): "); scanf("%d", &m); // assume user enters a valid integer >=0 total = 0; for(i=0; i

Answers:- given code:- #include <stdio.h> int main() { int n, m; int i, j, total;…

The program below reads two integers n and m from the user. Assume the user enters non-negative values for both. In terms of n and m, select the correct formula for the total value printed at the end of the program. #include int main() { int n, m; int i, j, total; printf("enter n (NON_NEGATIVE): "); scanf("%d", &n); // assume user enters a valid integer >= 0 } printf("enter m (NON_NEGATIVE: "); scanf("%d", &m); // assume user enters a valid integer >=0 total = 0; for(i=0; i

The program below reads two integers n and m from the user. Assume the user enters non-negative values for both. In terms of n and m, select the correct formula for the total value printed at the end of the program. #include int main() { int n, m; int i, j, total; printf("enter n (NON_NEGATIVE): "); scanf("%d", &n); // assume user enters a valid integer >= 0 } printf("enter m (NON_NEGATIVE: "); scanf("%d", &m); // assume user enters a valid integer >=0 total = 0; for(i=0; i

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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The assignment is a step-by-step assignment where you build on the previous step so Please added to the existing code #include <stdio.h> int printBin(int value); int main(){ int num=10; int tobinary= printBin(num); printf("The number %d converted to binary as %d \n ",num,tobinary); unsigned int x = 1; char *ccc = (char*)&x; if(*ccc){ printf("This is Little endian"); } else{ printf("This is Big endian"); } getchar(); return 0; } int printBin(int value) { if(value<2) return value; return printBin(value / 2) *10 + value % 2; }
please fast
How do you fix this?
Use cin to read integers from input until 1000 is read. For each remaining integer read before 1000, if the integer is positive, output the integer followed by a newline and add the integer to totalOfSelected. Ex: If the input is 8 24 15 -6 14 1000, then the output is: 8 24 15 14 The sum of all positive values is 61 #include <iostream> using namespace std; int main() { int inputValue; int totalOfSelected; /* Your code goes here */ cout << "The sum of all positive values is " << totalOfSelected << endl; return 0; }
2. What is the output of the following code ? #include int main() { int i=1; printf("%d%d%d",++i,i++, ++i); return (0); } a) 224 c) 334e b) 234 d) 422 VAS NO
find and fix error in this code
Use Kotlin
Use cin to read integers from input until 100 is read. For each remaining integer read before 100, if the integer is negative, output the integer followed by a newline and add the integer to sumOfNegative. Ex: If the input is 11 -14 -11 -4 100, then the output is: -14 -11 -4 The sum of all negative values is -29 #include <iostream> using namespace std; int main() { int inputNumber; int sumOfNegative; /* Your code goes here */ cout << "The sum of all negative values is " << sumOfNegative << endl; return 0; }
Need help only with the highlighted part no need for help with the code the code is just for reference #include <stdio.h> int printBin(int value); int main(){ int num=10; int tobinary= printBin(num); printf("The number %d converted to binary as %d",num,tobinary); unsigned int x = 1; char *ccc = (char*)&x; if(*ccc){ printf("This is Little endian"); } else{ printf("This is Big endian"); } getchar(); return 0; } int printBin(int value) { if(value<2) return value; return printBin(value / 2) *10 + value % 2; }
Need help only with the highlighted part no need for help with the code the code is just for reference #include <stdio.h> int printBin(int value); int main(){ int num=10; int tobinary= printBin(num); printf("The number %d converted to binary as %d",num,tobinary); unsigned int x = 1; char *ccc = (char*)&x; if(*ccc){ printf("This is Little endian"); } else{ printf("This is Big endian"); } getchar(); return 0; } int printBin(int value) { if(value<2) return value; return printBin(value / 2) *10 + value % 2; }