Below is the transcription of the provided C program and its explanation:```c#include int main() { int n, m; int i, j, total; printf("enter n (NON_NEGATIVE): "); scanf("%d", &n); // assume user enters a valid integer >= 0 printf("enter m (NON_NEGATIVE): "); scanf("%d", &m); // assume user enters a valid integer >= 0 total = 0; for(i=0; i 0) { total--; j--; } printf("total: %d\n", total); return 0;}```### Explanation:The program takes two non-negative integers, `n` and `m`, from the user and calculates a total based on those inputs.1. **Initialization:** - The program uses the `stdio.h` library for input and output functions. - Variables `n`, `m`, `i`, `j`, and `total` are declared as integers.2. **User Input:** - The user is prompted to enter two non-negative integers `n` and `m`.3. **Nested Loops:** - A nested loop structure is used: - The outer loop runs `n` times. - For each iteration of the outer loop, the inner loop runs `m` times. - The `total` variable is incremented in each iteration of the inner loop, resulting in `total = n * m`.4. **While Loop:** - A while loop is used to decrement `total` by `m`. This loop runs `m` times and therefore decreases `total` by `m`.5. **Output:** - Finally, the total is printed, which calculates to `n * m - m`.6. **Candidate Formulas:** - The options provided at the end likely reflect potential formulas for the total: - \( n \times m + m \) - \( n \) - \( n \times m - m \) - \( (n - 1) \times m \) Based on the code provided, the correct formula for the total is \( n

The program below reads two integers n and m from the user. As a function of n and m, give a formula for the total value printed at the end of the program. #include int main() { int n, m; int i, j, total; printf("enter n (NON_NEGATIVE): "); scanf("%d", &n); // assume user enters a valid integer >= 0 printf("enter m (NON_NEGATIVE: "); scanf("%d", &m); // assume user enters a valid integer >=0 total = 0; for(i=0; i0) { total--; j--; } printf("total: %d\n", total); return 0; Onxm+m Ⓒnxm-j (n-1) xm