The problem: You push a 20-kg lawn mower, exerting a 100-N force on it. You push 37° below the horizontal. The coefficient of kinetic friction between the grass and mower is 0.60. Determine the acceleration of the lawn mower. Assume that g= 10 N/kg.
The problem: You push a 20-kg lawn mower, exerting a 100-N force on it. You push 37° below the horizontal. The coefficient of kinetic friction between the grass and mower is 0.60. Determine the acceleration of the lawn mower. Assume that g= 10 N/kg.
University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter2: Vectors
Section: Chapter Questions
Problem 26P: In a tug-of-war game on one campus, 15 students pull on a rope at both ends in an effort to displace...
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Identify any errors in the solution to the following problem and provide a corrected solution.
![OALG 4.4.8 Evaluate the solution
Identify any errors in the solution to the following problem and provide a corrected solution if
needed.
The problem: You push a 20-kg lawn mower, exerting a 100-N force on it. You push 37° below
the horizontal. The coefficient of kinetic friction between the grass and mower is 0.60.
Determine the acceleration of the lawn mower. Assume that g=10 N/kg.
N
Proposed solution: The situation is pictured at the right.
The mower is the object of interest and is considered a
point-like object. The forces that other objects exert on the
mower are shown in the force diagram. The magnitude of
the kinetic friction force is:
Fy on M
f =4,N =0.60×(20 kg)x(10 N/kg) = 120 N
The acceleration of the mower is:
mg
a = (F-f)/m= [(100 N)-(120 N)]/(20 kg) =-1.0 m/s
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Transcribed Image Text:OALG 4.4.8 Evaluate the solution
Identify any errors in the solution to the following problem and provide a corrected solution if
needed.
The problem: You push a 20-kg lawn mower, exerting a 100-N force on it. You push 37° below
the horizontal. The coefficient of kinetic friction between the grass and mower is 0.60.
Determine the acceleration of the lawn mower. Assume that g=10 N/kg.
N
Proposed solution: The situation is pictured at the right.
The mower is the object of interest and is considered a
point-like object. The forces that other objects exert on the
mower are shown in the force diagram. The magnitude of
the kinetic friction force is:
Fy on M
f =4,N =0.60×(20 kg)x(10 N/kg) = 120 N
The acceleration of the mower is:
mg
a = (F-f)/m= [(100 N)-(120 N)]/(20 kg) =-1.0 m/s
%3D
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