The Problem: Members of the Town of Colonie Golfers' Lo raise concerns to Mr. Lange, as its leader, about how the league is run. T statistically even. In other words, members raise concerns that one or more most frequent concern raised is that the teams competing each week are not teams have a statistical advantage over other teams. of statistical hypothesis tests discussed in this course to evaluate the teams To evaluate the validity of these claims, Mr. Lange has decided to use a mix ances F Test, one is Welch's T Test, and the other is the 2-Sample T Test from Outing #14 in calendar-year 2016 (2016, #14). One is the Equal Vari- for Equal Means. In this particular outing, seven teams were competing for the win. A random sample of eight prior scores from each team member was collected, and the summary statistics are shown below (correct to three decimal places). Sample Variance Team Sample Size 1 24 32 32 32 32 32 32 2 3 4 5 6 7 Sample Mean 76.500 79.656 79.500 82.375 80.406 80.281 80.438 14.522 18.233 13.097 47.984 18.314 11.047 14.383 53² To test for statistical evenness among these teams using the mix of tests we described above, however, we will have to adjust the significance levels we are accustomed to using. Use the table on the next page to help you: If you are using... ... use 5% 0.238% 1% 0.048% 0.1% 0.005%

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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Complete both tables on the remaining pages and show your work for at least three Equal Variances F Tests and at least five T tests. You must show at least one computation using Welch’s T Test and at least one computation using the 2-Sample T Test for Equal Means.(I don't know how to find the distribution or probability for the first chart)

other numbers to three decimal places except
The Problem: Members of the Town of Colonie Golfers' Loop freque
raise concerns to Mr. Lange, as its leader, about how the league is run. The
most frequent concern raised is that the teams competing each week are not
statistically even. In other words, members raise concerns that one or more
teams have a statistical advantage over other teams.
To evaluate the validity of these claims, Mr. Lange has decided to use a mix
of statistical hypothesis tests discussed in this course to evaluate the teams
from Outing #14 in calendar-year 2016 (2016, #14). One is the Equal Vari-
ances F Test, one is Welch's T Test, and the other is the 2-Sample T Test
for Equal Means.
In this particular outing, seven teams were competing for the win. A random
sample of eight prior scores from each team member was collected, and the
summary statistics are shown below (correct to three decimal places).
Team Sample Size | Sample Mean | Sample Variance
1
24
32
32
32
32
32
32
2
3
4
5
6
7
76.500
79.656
79.500
82.375
80.406
80.281
80.438
14.522
18.233
13.097
47.984
18.314
11.047
14.383
To test for statistical evenness among these teams using the mix of tests we
described above, however, we will have to adjust the significance levels we
are accustomed to using. Use the table on the next page to help you:
If you are using...
use
5%
0.238%
1%
0.048%
0.1% 0.005%
1
53²
Transcribed Image Text:other numbers to three decimal places except The Problem: Members of the Town of Colonie Golfers' Loop freque raise concerns to Mr. Lange, as its leader, about how the league is run. The most frequent concern raised is that the teams competing each week are not statistically even. In other words, members raise concerns that one or more teams have a statistical advantage over other teams. To evaluate the validity of these claims, Mr. Lange has decided to use a mix of statistical hypothesis tests discussed in this course to evaluate the teams from Outing #14 in calendar-year 2016 (2016, #14). One is the Equal Vari- ances F Test, one is Welch's T Test, and the other is the 2-Sample T Test for Equal Means. In this particular outing, seven teams were competing for the win. A random sample of eight prior scores from each team member was collected, and the summary statistics are shown below (correct to three decimal places). Team Sample Size | Sample Mean | Sample Variance 1 24 32 32 32 32 32 32 2 3 4 5 6 7 76.500 79.656 79.500 82.375 80.406 80.281 80.438 14.522 18.233 13.097 47.984 18.314 11.047 14.383 To test for statistical evenness among these teams using the mix of tests we described above, however, we will have to adjust the significance levels we are accustomed to using. Use the table on the next page to help you: If you are using... use 5% 0.238% 1% 0.048% 0.1% 0.005% 1 53²
6
4
3
2
Teams to Compare Sample Variances
First
Second
First
Second
18.233
1
7
6
7
7
6
5
7
6
5
4
6
7
4
5
2
3
3
4
UT
6
5
7
14.522
18.233
13.097
47.984
18.314
11.047
13.097
47.984
18.314
11.047
14.383
13.097
47.984
18.314
11.047
14.383
47.984
18.314
11.047
14.383
18.314
11.047
14.383
11.047
14.383
14.383
3
f* Statistic
18.233
1.532
=
1.25554
13.097
14.527
M
0.90187
47.914
14.522 >
3.30423
1.26112
15.314
14.528>
11.047
14.522
14.35376071
4
14.522
0.99043
13.097
0.71831
47.984
18.233
2.63171
18.14
18.233
1.00444
11.047
18.233
0.60588
14.383
18.233 *
0.78884
47.984
73,097
3,66373
18.314
13.097
*
Test Results
Distribution
F/33, 23)
1.39833
1047
13,097 =
14.383
M
13.047
0.84348
1.09819
18.314
47.984
0.38167
11.047
47484
0.23022
14.383
47.984
0.29975
11.041
18.314
0.60320
14.383
18.314
0.78536
14.383
11.047 =
1.30198
Probability
зад.
Da.
b
C
Transcribed Image Text:6 4 3 2 Teams to Compare Sample Variances First Second First Second 18.233 1 7 6 7 7 6 5 7 6 5 4 6 7 4 5 2 3 3 4 UT 6 5 7 14.522 18.233 13.097 47.984 18.314 11.047 13.097 47.984 18.314 11.047 14.383 13.097 47.984 18.314 11.047 14.383 47.984 18.314 11.047 14.383 18.314 11.047 14.383 11.047 14.383 14.383 3 f* Statistic 18.233 1.532 = 1.25554 13.097 14.527 M 0.90187 47.914 14.522 > 3.30423 1.26112 15.314 14.528> 11.047 14.522 14.35376071 4 14.522 0.99043 13.097 0.71831 47.984 18.233 2.63171 18.14 18.233 1.00444 11.047 18.233 0.60588 14.383 18.233 * 0.78884 47.984 73,097 3,66373 18.314 13.097 * Test Results Distribution F/33, 23) 1.39833 1047 13,097 = 14.383 M 13.047 0.84348 1.09819 18.314 47.984 0.38167 11.047 47484 0.23022 14.383 47.984 0.29975 11.041 18.314 0.60320 14.383 18.314 0.78536 14.383 11.047 = 1.30198 Probability зад. Da. b C
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