The probability that it will rain is 0.35. The probability that Juan will go to the movies given that it rains is 0.60 and the probability that Juan will go to the movies if it does not rain is 0.90. a) Find the probability that Juan will go to the movies b) If Juan did not go to the movies, find the probablity that it rained

The probability that it will rain is 0.35. The probability that Juan will go to the movies given that it rains is 0.60 and the probability that Juan will go to the movies if it does not rain is 0.90. a) Find the probability that Juan will go to the movies b) If Juan did not go to the movies, find the probablity that it rained

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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The police station calls Robert an average of 2 times per hour to ask for his help. The probability that the station calls Robert in a time interval is dependent only on the length of the time interval and is independent of whether or not the department called Robert on any previous time interval. Superman goes on a date with Sally and picks her up from her place at 7:00pm. 1) What is the probability that their date has been interperated by 8:00pm? 2) If the number of times he is called is independent from one hour to the next, what is the probability that Robert and Sally can finish their 4 hour date uninterrupted? 3) What is the probability that the date is interrupted 5 times during the first hour and Sally decides to go back to the office? 4) What is the probability that the date is interrupted exactly 4 times during the first hour given that it is interrupted fewer than 6 times in the first hour?
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The probability that a man will be alive in 25 years is 3/5, and the probability that his wife will be alive in 25 years is 2/3. Determine the probability that, a) Both will be alive. b) Only the man will be alive. c) Only the wife will be alive. d) At least one will be alive. e) Neither will be alive.
Probability of taking route 1 is 30% and taking route 2 is 70%.The probability of being late to the meeting is 5% under the condition that route 1 is taken and 10% when route 2 is taken.a) Calculate the probability that he/she is late for the meeting.b) Given that he/she is late for the meeting, what is the probability that he/she used route 1?
A small convenience store has on average 30 customers per hour. a) Find the probability that in a 10 minute period 4 customers visit the store. b) Find the probability that in a 6 minute period fewer than 3 customers visit the store. c) Find the probability that in a 6 minute period more than 1 customer visits the store. can you solve this for me by showing step by step for each question
The drivers are given a choice about how to cross a river in a town. The choices are either to use the bridge or the tunel. Both of the two options have the same length and take the same time.Let's suppose that when it is raining 4 out of 5 drivers prefer to use the tunnel. In that case, what is the probability to observe 14 out of 60 drivers using the bridge?
pls help me do this the answer is 6.a) 0.1791 b) 13 days
A = 88 , B = 4 , C = 1
Need help pls!
810) See Ex. 809. a) Find the probability of obtaining 2 nonconforming units on the first sample of 2 and 1 nonconforming unit on the second sample of 2. b) What is the probability of 0 nonconforming units on the first sample and 1 nonconforming units on the second? The first sample is returned before the second sample is selected. ex 809 It is given that, the probability of obtaining 1 nonconforming unit in a sample of two is 0.39 and the probability of 2 nonconforming units in a sample of two is 0.16. Consider a random variable x that defines the number of nonconforming unit in the sample. Hence, according to question, P(X = 1) = 0.39 and P(X = 2) = 0.16. It is known that the sum of the probabilities is 1. That is, P(X = 0) + P(X = 1) + P(X = 2) = 1 P(X = 0) = 1 – P(X = 1) – P(X = 2) = 1 – 0.39 – 0.16 = 0.45. Thus, the probability of zero nonconforming units in a sample of two is 0.45.