The probability that it will rain is 0.35. The probability that Juan will go to the movies given that it rains is 0.60 and the probability that Juan will go to the movies if it does not rain is 0.90. a) Find the probability that Juan will go to the movies b) If Juan did not go to the movies, find the probablity that it rained

The probability that it will rain is 0.35. The probability that Juan will go to the movies given that it rains is 0.60 and the probability that Juan will go to the movies if it does not rain is 0.90. a) Find the probability that Juan will go to the movies b) If Juan did not go to the movies, find the probablity that it rained

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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The probability that it will rain is 0.35. The probability that Juan will go to the movies given that it rains is 0.60 and the probability that Juan will go to the movies if it does not rain is 0.90.

a) Find the probability that Juan will go to the movies

b) If Juan did not go to the movies, find the probablity that it rained

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810) See Ex. 809. a) Find the probability of obtaining 2 nonconforming units on the first sample of 2 and 1 nonconforming unit on the second sample of 2. b) What is the probability of 0 nonconforming units on the first sample and 1 nonconforming units on the second? The first sample is returned before the second sample is selected. ex 809 It is given that, the probability of obtaining 1 nonconforming unit in a sample of two is 0.39 and the probability of 2 nonconforming units in a sample of two is 0.16. Consider a random variable x that defines the number of nonconforming unit in the sample. Hence, according to question, P(X = 1) = 0.39 and P(X = 2) = 0.16. It is known that the sum of the probabilities is 1. That is, P(X = 0) + P(X = 1) + P(X = 2) = 1 P(X = 0) = 1 – P(X = 1) – P(X = 2) = 1 – 0.39 – 0.16 = 0.45. Thus, the probability of zero nonconforming units in a sample of two is 0.45.