**Text for Educational Website****Probability Problem: Visiting Canada and Mexico**The probability that a U.S. resident has visited Canada is 0.18. The probability that a U.S. resident has visited Mexico is 0.09. Furthermore, the probability that a U.S. resident has visited both countries is 0.04. Consider the events "has visited Canada" and "has visited Mexico," applied to a randomly-chosen U.S. resident. Are these two events independent? Are they disjoint? What can you say about these events?**Options:**- They are independent but not disjoint.- They are disjoint but not independent.- They are both independent and disjoint.- They are neither independent nor disjoint. **Question:**The probability of team A beating team B is \(\frac{3}{5}\). What is the probability that team A will win two consecutive games from team B?1. \(\frac{9}{25}\)2. \(\frac{4}{25}\)3. \(\frac{6}{25}\)4. \(\frac{16}{25}\)**Explanation:**To find the probability of team A winning two consecutive games, you multiply the probability of winning one game by itself:\[\left(\frac{3}{5}\right) \times \left(\frac{3}{5}\right) = \frac{9}{25}\]Therefore, the correct answer is \(\frac{9}{25}\).

Given problem Given that The probability that a U.S. resident has visited Canada is = 0.18 P( C…

Answered: The probability that a U.S. resident…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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