The probability that a person who exercises and eats well has a heart attack is predicted to be 0.5 for a population. If 18 persons are randomly and independently selected from this population and Y is the number of people that have heart attacks, the expected value for Y is and its standard deviation is

Q: A population has a mean of 80 and a standard deviation of 7. A sample of 49 observations will be…

A:

Q: A large population has a mean of 60 and a standard deviation of 8. A sample of 50 observations is…

A: GivenMean(μ)=60standard deviation(σ)=8sample size(n)=50

Q: A particular fruit's weights are normally distributed, with a mean of 768 grams and a standard…

A: Given, let X be the weight of fruits. The mean weight of the fruit’s is  The standard deviation of…

Q: If Y is a random variable with a mean of 10 and a standard deviation of 2, what is the probability…

A: From the provided information, Mean (µ) = 10 Standard deviation (σ) = 2

Q: A population has a mean of 200 and a standard deviation of 25. A sample of 64 observations will be…

A: We have to find out given probabiity..

Q: The average height of a certain age group of people is 53 inches. The standard deviation is 4…

A: Let "X" be the height of a certain age group of people in inches.

Q: The average height of a certain age group of people is 53 inches. The standard deviation is 4…

A: Let X be the random variable from normal distribution with mean or average (μ) = 53 and standard…

Q: population has a mean of 80 and a standard deviation of 7. A sample of 49 observations will be…

A: Sampling Distribution of a Normal Variable : Given a random variable X. Suppose that the population…

Q: A particular fruit's weights are normally distributed, with a mean of 557 grams and a standard…

A: From the given information, let X be the fruit’s weights. Here, X follows normally distribution with…

Q: The net weight of a can of salmon is a random variable with a mean of 6.07 ounces and a standard…

A:

Q: The population mean for the average weigh of 12 year old children is 102 pounds and the population…

A: Solution: Let X be the weight of 12 year old children. From the given information, µ=102 pounds,…

Q: the weights of 8000 men follows a normal distribution with mean 67 kg. and the standard deviation 10…

A: We want to find probability for given data

Q: Suppose you have a distribution, X, with mean = 15 and standard deviation = 6. Define a new random…

A: It is given that  Mean of X, E(X) = 15 Standard deviation of X, SD(X) = 6 Variance of X, Var(X) = 62…

Q: A population has a mean of 80 and a standard deviation of 7.A sample of 49 observation will be…

A:

Q: The average number of pounds of red meat a person consumes each year is 196 with a standard…

A: We are given,μ = 196σ = 22n = 60

Q: P(x) 0.645 1. 0.297 0.052 0.005 0.001 0.000 2345

A: We have to use following formulae , Standard deviation : σ = ∑( x - μ)2p(x) Where , μ is mean μ =…

Q: Suppose the probability a patient will recover from a disease following medication is 0.7. In a…

A: Given : the probability a patient will recover from a disease following medication is 0.7.  In a…

Q: The net weight of a can of salmon is a random variable with a mean of 6.21 ounces and a standard…

A: Solution

Q: Find the probability that an observation taken from a standard normal population will be more than…

A: We have to find given probability..

Q: goods

A: Let X be the random variable such that  cholesterol content of a certain canned goods. The average…

Q: The average GPA scored by a class is 4.91 and standard deviation is 0.72. For a sample of 30…

A:

Q: Suppose the average age of a Tulane undergraduate is 20 years with a standard deviation of 1.2…

A:

Q: The average age of managers is 40 years. Assume the variable is normally distributed. If the…

A: Given data,μ=40σ=5P(35<X<46)=?

Q: When a normal random variable Y is transformed to a standard normal random variable Z, the mean…

A: When a normal random variable Y is transformed to a standard normal random variable Z, the mean…

Q: A population has a mean of 80 and a standard deviation of 7. A sample of 49 survey will be taken.…

A: Given Data: Let X represent the random variable Mean=80 SD=7   n=49 M~ Normal(80,7249)

Q: In a population of normally distributed data, the mean is 68 and the standard deviation is 12.75.…

A: given data normal distributionμ = 68σ = 12.75sample size (n) = 25P(70<x¯<75) = ?

Q: opulation has an average of 125 and a standard deviation of 15.  Calculate the probability that in a…

A: given data, μ=125σ=15n=75p(x¯>130)=?

Q: A population has a mean of 90 and a standard deviation of 10. A sample of 100 observations will be…

A:

Q: University students' blood pressure can be expected to follow a normal distribution with a mean of…

A:

Q: A particular fruit's weights are normally distributed, with a mean of 257 grams and a standard…

A:

Q: If Y is a random variable with a mean of 30 and a standard deviation of 10, what is the probability…

A: Let Y be the random variable from normal distribution with mean (μ) = 30 and standard deviation (σ)…

Q: probability that a patient recovers from a rare blood disease is 0.4. If 15 people are known to have…

A: Given problem is binomial distribution Let, X: Patient recovers from a rare blood disease p=Prob. of…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.