The probability that a person in the United States has type B* blood is 9%. Five unrelated people in the United States are selected at random. Complete parts (a) through (d). (a) Find the probability that all five have type B* blood. The probability that all five have type B* blood is. (Round to six decimal places as needed.) (b) Find the probability that none of the five have type B* blood. The probability that none of the five have type B* blood is. (Round to three decimal places as needed.) (c) Find the probability that at least one of the five has type B* blood. The probability that at least one of the five has type B* blood is. (Round to three decimal places as needed.) (d) Which of the events can be considered unusual? Explain. Select all that apply. O A. None of these events are unusual. OB. The event in part (a) is unusual because its probability is less than or equal to 0.05. C. The event in part (b) is unusual because its probability is less than or equal to 0.05. D. The event in part (c) is unusual because its probability is less than or equal to 0.05.

The probability that a person in the United States has type B* blood is 9%. Five unrelated people in the United States are selected at random. Complete parts (a) through (d). (a) Find the probability that all five have type B* blood. The probability that all five have type B* blood is. (Round to six decimal places as needed.) (b) Find the probability that none of the five have type B* blood. The probability that none of the five have type B* blood is. (Round to three decimal places as needed.) (c) Find the probability that at least one of the five has type B* blood. The probability that at least one of the five has type B* blood is. (Round to three decimal places as needed.) (d) Which of the events can be considered unusual? Explain. Select all that apply. O A. None of these events are unusual. OB. The event in part (a) is unusual because its probability is less than or equal to 0.05. C. The event in part (b) is unusual because its probability is less than or equal to 0.05. D. The event in part (c) is unusual because its probability is less than or equal to 0.05.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Concept explainers

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

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The probability that a person in the United States has type B* blood is 9%. Five unrelated people in the United States
are selected at random. Complete parts (a) through (d).
(a) Find the probability that all five have type B* blood.
The probability that all five have type B* blood is
(Round to six decimal places as needed.)
(b) Find the probability that none of the five have type B* blood.
The probability that none of the five have type B* blood is.
(Round to three decimal places as needed.)
(c) Find the probability that at least one of the five has type B* blood.
The probability that at least one of the five has type B* blood is.
(Round to three decimal places as needed.)
(d) Which of the events can be considered unusual? Explain. Select all that apply.
O A. None of these events are unusual.
O B. The event in part (a) is unusual because its probability is less than or equal to 0.05.
O C. The event in part (b) is unusual because its probability is less than or equal to 0.05.
O D. The event in part (c) is unusual because its probability is less than or equal to 0.05.

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