The probability of winning a certain lottery is 1/51,949. For people who play 560 times, find the standard deviation for the random variable X, the number of wins. 0.1223 0.1038 0.0108 0.1137 2.4569
The probability of winning a certain lottery is 1/51,949. For people who play 560 times, find the standard deviation for the random variable X, the number of wins. 0.1223 0.1038 0.0108 0.1137 2.4569
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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10.
![**Probability and Statistics: Calculating Standard Deviation in a Lottery Scenario**
The probability of winning a certain lottery is \( \frac{1}{51,949} \). For individuals who play 560 times, the task is to find the standard deviation for the random variable \( X \), representing the number of wins.
Choices:
- \( 0.1223 \)
- \( 0.1038 \)
- \( 0.0108 \)
- \( 0.1137 \)
- \( 2.4569 \)
In this scenario, use the formula for the standard deviation of a binomial distribution, where the standard deviation \( \sigma \) is given by:
\[
\sigma = \sqrt{n \cdot p \cdot (1-p)}
\]
- \( n = 560 \) (number of trials)
- \( p = \frac{1}{51,949} \) (probability of success on each trial)
Calculate \( \sigma \) using the given values to find the correct answer from the choices above.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe5247ce5-a3e5-4e1f-ba29-c615e03ea9bd%2F4f20f8a3-9411-4cff-83cc-8808c10d735b%2Flvnci99_processed.png&w=3840&q=75)
Transcribed Image Text:**Probability and Statistics: Calculating Standard Deviation in a Lottery Scenario**
The probability of winning a certain lottery is \( \frac{1}{51,949} \). For individuals who play 560 times, the task is to find the standard deviation for the random variable \( X \), representing the number of wins.
Choices:
- \( 0.1223 \)
- \( 0.1038 \)
- \( 0.0108 \)
- \( 0.1137 \)
- \( 2.4569 \)
In this scenario, use the formula for the standard deviation of a binomial distribution, where the standard deviation \( \sigma \) is given by:
\[
\sigma = \sqrt{n \cdot p \cdot (1-p)}
\]
- \( n = 560 \) (number of trials)
- \( p = \frac{1}{51,949} \) (probability of success on each trial)
Calculate \( \sigma \) using the given values to find the correct answer from the choices above.
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