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The probability distribution of X, the number of males with tinnitus (ringing ears) among 6 randomly selected males, is as follows: 0 Xi P(X = x₁) 0.61 P(X=4)=0.02 X=1 P(X=4) |P(X=4)=0.02 |X=1 P(X=4) 1 P(X=4)=0.02 X=1 P(X=4) 0.24 2 0.08 3 0.04 4 0.02 1. Use the random variable notation to express symbolically each of the following: 5 0.01 2. Use the above probability distribution table to find the following: a. P(X ≤ 0) = b. P(X= 3 or X = 4) c. P(X > 0) An event in which the number of males with tinnitus is exactly 1. 6 0 (Round the answer to 2 decimals) The probability of an event in which the number of males with tinnitus is exactly 4 is equal to 0.02. The probability of an event in which the number of males with tinnitus is exactly 4. (Round the answer to 2 decimals) Total (Round the answer to 2 decimals) 1

The probability distribution of X, the number of males with tinnitus (ringing ears) among 6 randomly selected males, is as follows: 0 Xi P(X = x₁) 0.61 P(X=4)=0.02 X=1 P(X=4) |P(X=4)=0.02 |X=1 P(X=4) 1 P(X=4)=0.02 X=1 P(X=4) 0.24 2 0.08 3 0.04 4 0.02 1. Use the random variable notation to express symbolically each of the following: 5 0.01 2. Use the above probability distribution table to find the following: a. P(X ≤ 0) = b. P(X= 3 or X = 4) c. P(X > 0) An event in which the number of males with tinnitus is exactly 1. 6 0 (Round the answer to 2 decimals) The probability of an event in which the number of males with tinnitus is exactly 4 is equal to 0.02. The probability of an event in which the number of males with tinnitus is exactly 4. (Round the answer to 2 decimals) Total (Round the answer to 2 decimals) 1

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question 5 The probability distribution of X, the number of males with tinnitus (ringing ears) among 6 randomly selected males, is as follows: 0 Xi P(X = x₁) 0.61 P(X=4)=0.02 X=1 P(X=4) P(X=4)=0.02 |X=1 P(X=4) 1 P(X=4)=0.02 |X=1 P(X=4) 0.24 2 0.08 3 0.04 4 1. Use the random variable notation to express symbolically each of the following: 0.02 5 0.01 An event in which the number of males with tinnitus is exactly 1. 2. Use the above probability distribution table to find the following: a. P(X ≤ 0): b. P(X=3 or X = 4) c. P(X > 0) 6 0 (Round the answer to 2 decimals) The probability of an event in which the number of males with tinnitus is exactly 4 is equal to 0.02. The probability of an event in which the number of males with tinnitus is exactly 4. (Round the answer to 2 decimals) Total (Round the answer to 2 decimals) 1
Transcribed Image Text:Question 5 The probability distribution of X, the number of males with tinnitus (ringing ears) among 6 randomly selected males, is as follows: 0 Xi P(X = x₁) 0.61 P(X=4)=0.02 X=1 P(X=4) P(X=4)=0.02 |X=1 P(X=4) 1 P(X=4)=0.02 |X=1 P(X=4) 0.24 2 0.08 3 0.04 4 1. Use the random variable notation to express symbolically each of the following: 0.02 5 0.01 An event in which the number of males with tinnitus is exactly 1. 2. Use the above probability distribution table to find the following: a. P(X ≤ 0): b. P(X=3 or X = 4) c. P(X > 0) 6 0 (Round the answer to 2 decimals) The probability of an event in which the number of males with tinnitus is exactly 4 is equal to 0.02. The probability of an event in which the number of males with tinnitus is exactly 4. (Round the answer to 2 decimals) Total (Round the answer to 2 decimals) 1
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