The probability distribution of x, the number of defective tires on a randomly selected automobile checked at a certain inspection station, is given in the following table. X 0 1 2 .52 .12 .08 p(x) (a) Calculate the mean value of x. Mx 3 .04 4 .24 (b) What is the probability that x exceeds its mean value? P(x > M₂) =

Q: 5. 8. 45°

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A: Simply transpose as shown to get value of x

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A: Please see the explanation below

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