The probability distribution model of winning a gambling game is given as:\[\begin{array}{|c|c|c|c|}\hlineX & \$40 & \$0 & -\$10 \\\hlineP(X) & \frac{1}{6} & \frac{5}{36} & \frac{25}{36} \\\hline\end{array}\]Find the standard deviation of prospective winnings. (Round to two decimal points and write in XX.XX format.)

The probability distribution model of winning a gambling game is given as: X P(X) $40 1/1/00 $0 5 36 -$10 25 36 Find the standard deviation of prospective winnings. (Round to two decimal points and write in XX.XX format.)

The probability distribution model of winning a gambling game is given as: X P(X) $40 1/1/00 $0 5 36 -$10 25 36 Find the standard deviation of prospective winnings. (Round to two decimal points and write in XX.XX format.)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The standard deviation of the scores: 2, 1, 1, 8 is O 1.71 2 2.92 O.8.5
Normal probability plots for three data sets are shown below. Which plot indicates that the data are approximately normally distributed? C. A. O O O O Plot B Plot A Plot C Plots A and B B. Q ME
Verify whether the given table represents a probability distribution. In those cases where a probability distribution is described, find the mean and standard deviation. NOTE: The Rounding Rule for the mean and standard deviation: They should be rounded to one more decimal place than occurs in the raw data. For a group of four students, the number y who takes the Calculus II class next semester is given by this table. y P(y) 0 0.5131 1 0.3139 2 0.0624 3 0.1102 4 0.2002 Probability distribution with μ=0.4 and σ=0.4 Probability distribution with μ=0.6 and σ=0.1 Probability distribution with μ=0.6 and σ=0.3 Probability distribution with μ=0.7 and σ=0.4
Let X be the number of workouts a person does in a week. Suppose that X has the following probability distribution: 3 e d C # $ SB 4 C A. What is the expected number of workouts a person Standard deviation = r Expected value B. What is the standard deviation of the number of workouts a person f V You can use the tool below to help you compute standard deviation. % 5 t ca b 6 X 0 P p| 0.09 Oll y h hop & 7 n 1 2 3 0.14 0.43 | 0.25 O u does per Round to 2 decimal places, as needed. does per week? j Round to 2 decimal places, as needed. * 00 week? 8 4 0.09 3 k ( 9 O < alt O р ctrl [ ? + 11 = 1 < backs 1
Find the mean, variance and standard deviation for the probability distribution given below: X -5 2 12 10 P(X) 0.553 0.136 0.213 0.098
Quiz: Self-Check 3.2 This Question: 1 pt 5 of 8 (4 cor Complete parts (a) and (b) below. The number of dogs per household in a small town Dogs 3 4 Probability 0.662 0.212 0.083 0,022 0.013 0.008 (a) Find the mean, variance, and standard deviation of the probability distribution. Find the mean of the probability distribution. 卫三 (Round to one decimal place as needed.) Find the variance of the probability distribution. (Round to one decimal place as needed.) Find the standard deviation of the probability distribution. | (Round to one decimal place as needed.) (b) Interpret the results in the context of the real-life situation. Click to selecCt your answer(S). Video Tuterial How to Find Probablitie T1-84. =earch
Assume that adults have IQ scores that are normally distributed with a mean of μ=105 and a standard deviation σ=15. Find the probability that a randomly selected adult has an IQ between 90 and 120. Click to view page 1 of the table. LOADING... Click to view page 2 of the table. LOADING... Question content area bottom Part 1 The probability that a randomly selected adult has an IQ between 90 and 120 is enter your response here. (Type an integer or decimal rounded to four decimal places as needed.)
Find the mean, variance and standard deviation for the probability distribution given below: X -3 3 8 10 P(X) 0.597 0.13 0.215 0.058 A. Mean = B. Variance = C. Standard Deviation =
In a statistics exam an individuals score is normally distributed with a mean of 80 and a sample standard deviation of 8 points. Assume there are 30 individuals in the class. Calculate the probability the class average is less than 78. 58% 8.5% 21% 91.5% 42%
A=36 B=09 C=09 D=36
In a study, 25,000 adults were randomly surveyed as to the number of grandchildren they have, X. The probability distribution is given below. Find the mean and the standard deviation of the probability distribution using a TI-83, TI-83 Plus, or TI-84 graphing calculator. Round the mean to one decimal place and the standard deviation to two decimal places. x P(x) 0 0.01 1 0.02 2 0.02 3 0.24 4 0.35 5 0.20 6 0.07 7 0.05 8 0.02 9 0.01 10 0.01
Find the variance of the probability distribution for the histogram shown.