The probability distribution model of winning a gambling game is given as: $40 1 6 X P(X) $0 5 36 -$10 25 36 Find the expected value of prospective winnings. (Round to two decimal points and in 0.XX format.)
The probability distribution model of winning a gambling game is given as: $40 1 6 X P(X) $0 5 36 -$10 25 36 Find the expected value of prospective winnings. (Round to two decimal points and in 0.XX format.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question
Find the
![The probability distribution model of winning a gambling game is given as:
\[
\begin{array}{|c|c|c|c|}
\hline
X & \$40 & \$0 & -\$10 \\
\hline
P(X) & \frac{1}{6} & \frac{5}{36} & \frac{25}{36} \\
\hline
\end{array}
\]
Find the expected value of prospective winnings. (Round to two decimal points and write in 0.XX format.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F16008139-d6e2-4ae2-b2fa-8f3b60dc6bfa%2F2106346b-a813-4158-987c-9fc306c783f6%2Ff74qfz_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The probability distribution model of winning a gambling game is given as:
\[
\begin{array}{|c|c|c|c|}
\hline
X & \$40 & \$0 & -\$10 \\
\hline
P(X) & \frac{1}{6} & \frac{5}{36} & \frac{25}{36} \\
\hline
\end{array}
\]
Find the expected value of prospective winnings. (Round to two decimal points and write in 0.XX format.)
Expert Solution
Step 1
| X | $40 | $0 | -$10 |
| P(X) | 1/6 | 5/36 | 25/36 |
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Solved in 2 steps
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