The probability density function of R.V X is defined by: (6 (x² + 0. 5xy), 0 < x< 1, 0 < y< 2 fxv (x, y) = otherwise f) Obtain the probability of P(X < 1,Y < 2). g) Obtain fy(y) and f x¡y(x|y). h) Obtain E{X|Y = 1. 5} and E{X²|Y = 1. 5} , VAR{X|Y = 1.5}.
The probability density function of R.V X is defined by: (6 (x² + 0. 5xy), 0 < x< 1, 0 < y< 2 fxv (x, y) = otherwise f) Obtain the probability of P(X < 1,Y < 2). g) Obtain fy(y) and f x¡y(x|y). h) Obtain E{X|Y = 1. 5} and E{X²|Y = 1. 5} , VAR{X|Y = 1.5}.
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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![The probability density function of R.V X is defined by:
fxy (x, y) =
(x² + 0. 5xy),
0 < x < 1,
0 < y< 2
otherwise
f) Obtain the probability of P(X< 1,Y < 2).
g) Obtain fy(y) and f x¡y(x|y).
h) Obtain E{X|Y = 1. 5} and E{X²|Y = 1.5} , VAR{X|Y = 1.5}.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd89bb984-dbdb-4319-a6d9-ddf6d952a6eb%2Fbbaba661-43d4-426b-9b3e-5c47d968d166%2Foqswijm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The probability density function of R.V X is defined by:
fxy (x, y) =
(x² + 0. 5xy),
0 < x < 1,
0 < y< 2
otherwise
f) Obtain the probability of P(X< 1,Y < 2).
g) Obtain fy(y) and f x¡y(x|y).
h) Obtain E{X|Y = 1. 5} and E{X²|Y = 1.5} , VAR{X|Y = 1.5}.
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