The probability density function of a continuous random variable is: 4 (1+x) if -1 < x < 0 x < 0) 5 f(x) = 4 3 if 0 ≤ x <= < 15 Derive the distribution function of ! (Solution: (3 - 2x) 0, if xse1
The probability density function of a continuous random variable is: 4 (1+x) if -1 < x < 0 x < 0) 5 f(x) = 4 3 if 0 ≤ x <= < 15 Derive the distribution function of ! (Solution: (3 - 2x) 0, if xse1
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![4. The probability density function of a continuous random variable } is:
(1 + x)
f(x) =
if -1 < x < 0
3
(3 - 2x)
if 0 ≤ x < ₂
< ²³/
15
Derive the distribution function of !
(Solution:
0,
if x≤e1
if-1<x<0
(x+1),
F(x):
if 0 < x <=
15
3
1, if x ≥ 1/7/2
Little help: F(x) in 3/2 should converge to 1, and in -1 to 0!)
=
(2x − 3)²,
3
N/W](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F27650db4-f5f1-4bc5-af14-df805f1811e9%2Ff6c2c990-aa4b-4b83-9e57-9f0e4a83e5df%2Foypcsy_processed.png&w=3840&q=75)
Transcribed Image Text:4. The probability density function of a continuous random variable } is:
(1 + x)
f(x) =
if -1 < x < 0
3
(3 - 2x)
if 0 ≤ x < ₂
< ²³/
15
Derive the distribution function of !
(Solution:
0,
if x≤e1
if-1<x<0
(x+1),
F(x):
if 0 < x <=
15
3
1, if x ≥ 1/7/2
Little help: F(x) in 3/2 should converge to 1, and in -1 to 0!)
=
(2x − 3)²,
3
N/W
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