The probabilities that a marketinspector will discover violations ofthe public health code in a publicmarket are given in the followingtable. What is the probability that amarket inspector will discover, atleast two, but fewer than fourviolations of the public healthcode?(X)P(X)00.4110.2220.1730.1340.0550.02

Answered: The probabilities that a market…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Insurance: An insurance company sells a 1-year term life insurance policy to an 80-year-old man. The man pays a premium of $1200. If he dies within 1 year, the company will pay $21,000 to his beneficiary. According to the U.S. Centers for Disease Control and Prevention, the probability that an 80-year-old man will be alive 1 year later is 0.9437. Let X be the profit made by the insurance company. Part: 0 / 2 Part 1 of 2 (a) Find the probability distribution. The probability distribution is 1200 P(x)
The following table contains the probability distribution for X = the number of re-transmissions necessary to successfully transmit a 5 GB data package through a double satellite media. X P(x) 0 0.40 1 0.30 2 0.25 3 0.05 Find the probability that there is at most two re-transmission. The probabilities that discipline officers will discover violations of the student handbook in a certain school in a quarter are given in the following table. Number of Violations (v) 3 4 5 6 7 8 9 Probability P(v) 0.3100 0.1200 0.1700 0.1200 0.1300 0.1000 0.0500 What is the probability that on a given day, discipline officers will discover at most 6 violations of the student handbook? (Input answer in 4 decimal places) type your answer...
The chance of an IRS audit for a tax return with over $25,000 in income is about 2% per year. We are interested in the expected number of audits a person with that income has in a 16-year period. Assume each year is independent. Part (a) Part (b) List the values that X may take on. X=0, 1, 2,..., 15, 16 OX= 1, 2, 3, OX= 1, 2, 3, OX=1,2,3,... 15, 16 98, 99, 100 Part (c) Give the distribution of X X-B 0.02 □ Part (d) How many audits are expected in a 16-year period? (Round your answer to two decimal places.) 0.32 audits Part (e) Find the probability that a person is not audited at all. (Round your answer to four decimal places.) Part (1) Find the probability that a person is audited more than twice. (Round your answer to four decimal places.)
Let X = {Email, In Person, Instant Message, Text Message}; P(Email) = 0.06 P(In Person) = 0.55 P(Instant Message) = 0.24 P(Text Message) = 0.15 Is this model a probability distribution? A. Yes. B. No. C. Maybe.
Suppose that 20,000 married adults in a country were randomly surveyed as to the number of children they have. The results are compiled and are used as theoretical probabilities. Let X = the number of children married people have. P(x) ХP(x) 0.15 1 0.25 0.35 4 0.10 0.05 6 (or more) 0.05 (a) Find the probability that a married adult has three children. (Enter your answer to two decimal places.) (b) In words, what does the expected value in this example represent? O the average number of children married adults in the country have the average number of children adults in the country have O the number of children married adults in the country have O the number of children adults in the country have (c) Find the expected value. (Enter your answer to two decimal place.) children (d) Is it more likely that a married adult will have two to three children or four to six children? How do you know? O it is more likely to have two to three children, with p = 0.35 O it is more likely to have four…
Calculate the probability of 3 or 4 based on the following probability distribution. 1 4 p(x) 0.2 0.1 0.3 0.8 O0.6 O 0.7 er
Insurance: An insurance company sells a 1-year term life insurance policy to an 79-year-old woman. The woman pays a premium of $1800. If she dies within 1 year, the company will pay $39,000 to her beneficiary. According to the U.S. Centers for Disease Control and Prevention, the probability that an 79-year-old woman will be alive 1 year later is 0.9561. Let X be the profit made by the insurance company. Part 1 of 2 (a) Find the probability distribution. The probability distribution is X -37200 1800 P(x) 0.0439 0.9561 Alternate Answer: X P(x) Part: 1 / 2 Part 2 of 2 - 37,200 1800 0.0439 0.9561 (b) Find the expected value of the profit. Expected value of the profit is S X 00
Find the probability P(Ec) if P(E)=0.17.
The probability distribution given below represents the projected profit (in thousands of dollars) earned from a business over a year. Profit (x) in thousands of dollars f(x) -100 0.05 -50 0.15 0 0.30 50 0.35 100 0.12 200 0.03 a.) What is the probability that the business will operate at a loss for the year? b.) What is the probability that the business will break even? c.) What is the expected value for profit? Fill out the table below to help you calculate the value.
Insurance: An insurance company sells a 1-year term life insurance policy to an 84-year-old woman. The woman pays a premium of $1400. If she dies within 1 year, the company will pay $46,000 to her beneficiary. According to the U.S. Centers for Disease Control and Prevention, the probability that an 84-year-old woman will be alive 1 year later is 0.9714. Let X be the profit made by the insurance company. Part: 0 / 2 Part 1 of 2 (a) Find the probability distribution. The probability distribution is x 1400 X P(x)

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