b. an odd number?P (odd) =0.00c. a value greater than 3?P(> 3) =0.00d. a value less than 3?P(<3) =0.00 The probabilities of the outcomes of rolling a loaded (unfair) 6-sided die are as follows:P(1) = 0.15 P (2) :=If the die is rolled once, what is the probability of obtaining:a. a 3 or a 5?P (3 or 5) =0.15 P (3) = 0.10 P (4) = 0.15 P (5) = 0.10 P (6) = 0.350.00

given data, p(1)=0.15p(2)=0.15p(3)=0.10p(4)=0.15p(5)=0.10p(6)=0.35we have to find out the given…

Answered: The probabilities of the outcomes of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You are enrolled in MBA 440. At the beginning of the semester, you used your hunch to estimate the likelihood of passing this class. Let P be the event of passing the class; F is the event of failing the class. Your prior probabilities are as follows: P(P)=0.7 P(F)=0.3 After the first week of class, you find out that you have failed the first assignment. Let A1 be the event of passing the first assignment; let A2 be the event of failing the first assignment. Now you feel you need to update your belief about the likelihood of passing this class. You talk to your Professor and she tells you that given someone has passed the class, the probability of passing the first assignment is 0.8, i.e. P(A1|P)=0.8. She also gives you the following conditional probabilities: P(A2|P)=0.2; P(A1|F)=0.3 and P(A2|F)=0.7. What is the posterior probability that you will pass this class given that you have failed the first assignment?
Attached is the question. The word that is slightly cut off is characteristics.
Given the probability that "she's up all night 'til the sun" OR "she's up all night for good fun" is 0.37, the probability that "she's up all night for good fun" is 0.37, and the probability that "she's up all night 'til the sun" AND "she's up all night for good fun" is 0.34, what's the probability that "she's up all night 'til the sun"?
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If the weight (in grams) of cereal in a box of Lucky Charms is N(485,3), what is the probability that the box will contain less than the advertised weight of 474 g? Note: You may need to use Excel to calculate the exact probabilities. (Round your answer to 5 decimal places.)
Let S be the educational attainment of individuals in a town, with values S-0 for less than high school and S=1 for high school or above. Also, let Y be their individual annual income with values Y-O for less than $20,000, Y-1 for between $20,000 and $40,000, and Y=2 for above $40,000. Consider now the following joint probabilities: Y-0 (less than $20K) Y-1 ($20K-$40K) Y-2 (more than $40K) 0.03 0.01 0.36 0.33 SIY S-0 (Less than HS) 0.05 Y-1 (HS or more) 0.22 Determine the conditional standard deviation of the level of educational attainment given that the individual annual income is between $20,000 and $40,000.
Find the probability P(Ec) if P(E)=0.17.
Given the probability that "she's up all night 'til the sun" OR "she's up all night for good fun" is 0.38, the probability that "she's up all night for good fun" is 0.44, and the probability that "she's up all night 'til the sun" is 0.33, what's the probability that "she's up all night 'til the sun" AND "she's up all night for good fun"? Round to 2 decimal places as needed.
Given the probability that "she's up all night 'til the sun" OR "she's up all night for good fun" is 0.31, the probability that "she's up all night for good fun" is 0.20, and the probability that "she's up all night 'til the sun" AND "she's up all night for good fun" is 0.35, what's the probability that "she's up all night 'til the sun"?

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The probabilities of the outcomes of rolling a loaded (unfair) 6-sided die are as follows: P(1) = 0.15 P (2) = 0.15 P (3) = 0.10 P (4) = 0.15 P (5) = 0.10 P (6)=0.35 If the die is rolled once, what is the probability of obtaining: