Decision Alternative Produce pilot, d₁ Sell to competitor, d₂ Reject, 81 -100 100 State of Nature 1 Year, 82 50 100 2 Years, 83 150 100 The probabilities for the states of nature are P(8₁) = 0.20, P(82) = 0.30, and P(83) = 0.50 . For a consulting fee of $5000, an agency will review the plans for the comedy series and indicate the overall chances of a favorable network reaction to the series. Assume that the agency review will result in a favorable (F) or an unfavorable (U) review and that the following probabilities are relevant: P(F) = 0.69 P(U) = 0.31 P($1F) = 0.09 P(82|F) = 0.26 P(83| F) = 0.65 P($₁|U) = 0.45 P(82|U) = 0.39 P(83|U) = 0.16

FINANCIAL ACCOUNTING
10th Edition
ISBN:9781259964947
Author:Libby
Publisher:Libby
Chapter1: Financial Statements And Business Decisions
Section: Chapter Questions
Problem 1Q
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Related questions
Question
Decision
Alternative
Produce pilot,
d₁
Sell to
competitor,
d₂
Reject,
81
-100
100
State of Nature
1 Year, 82
50
100
2 Years,
83
150
100
Transcribed Image Text:Decision Alternative Produce pilot, d₁ Sell to competitor, d₂ Reject, 81 -100 100 State of Nature 1 Year, 82 50 100 2 Years, 83 150 100
The probabilities for the states of nature are P(8₁) = 0.20,
P(82) = 0.30, and P(83) = 0.50 . For a consulting fee of $5000, an
agency will review the plans for the comedy series and indicate the
overall chances of a favorable network reaction to the series. Assume
that the agency review will result in a favorable (F) or an unfavorable
(U) review and that the following probabilities are relevant:
P(F) = 0.69
P(U) = 0.31
P($1F) = 0.09
P(82|F) = 0.26
P(83| F) = 0.65
P($₁|U) = 0.45
P(82|U) = 0.39
P(83|U) = 0.16
Transcribed Image Text:The probabilities for the states of nature are P(8₁) = 0.20, P(82) = 0.30, and P(83) = 0.50 . For a consulting fee of $5000, an agency will review the plans for the comedy series and indicate the overall chances of a favorable network reaction to the series. Assume that the agency review will result in a favorable (F) or an unfavorable (U) review and that the following probabilities are relevant: P(F) = 0.69 P(U) = 0.31 P($1F) = 0.09 P(82|F) = 0.26 P(83| F) = 0.65 P($₁|U) = 0.45 P(82|U) = 0.39 P(83|U) = 0.16
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