The principle value of (1 + i)¹** isa) (1+i) expi+-log 22π4π i4 2b) (1+i) expc)d) (1 + i)exp(-+-log2)4-log 2(1-i)exp(-+-log 2)4 2

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Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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For the questions below, you will need to use Maple syntax for expressions: Expression How to enter t-2 + t2 V1-2t t^(-2) + t^2 + sqrt ( 1 - 2* 4+5t3 t)/(4+5*t^3) 4e5t 4*exp (5*t) Int = log t = loge t in (t) sin (t), cos (t), tan (t) , sin t, cos t, tan t, sec t, csc t sec (t), csc (t) sin t, cos-lt, arcsin (t), arccos (t), tan arctan (t) Note: the parentheses () must be present in the evaluation of functions, even if just evaluating at t. For instance, it is sin (t), not sin t. Note that you must enter exact answers, for example, for 1/3 do not enter a decimal approximation such as 0.3333333333. For negative denominators you must use brackets, for example, -3/2 or 3/ (-2) but not 3/-2. Enter Pi and exp (1) for T and the Euler number e. You are given the integral 64x2 81 -dx. I = 6x In order to compute this integral, we may attack this using the substitution x = sec t. a) We start by noting that da = f(t) dt, where f(t) = (enter your answer in valid maple syntax) b) Consequently, the…
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9. Solve each question below – show all steps for full marks and reject all extraneous roots! a. 4x-2 + 4x-1 = 20 b. -8log2(x-1) = -32 c. log4(x-3) + log4(x+3) = 2
The number of positive integers satisfying x + log10 (2* + 1) log105 + log106 is ... = x
1) Solve: 82x-5 32-6 2) Solve: In x In(x 4) ln(3x - 10) Solve: 2 ln(4 3x) 1 = 7 3) Solve: log2 x = 4 - log2(x - 6) 4)
7. Problem 8.3.14: Determine whether the given set of vectors is linearly dependent or linearly independent. U1 = (2,1,1,5), ūz = (2,2,1,1), ūz = (3,–1,6,1), ū4 = (1,1,1,–1)
Find the exact value of the following: 1) 931-1 33x+2 = 2) log₂ (x+4)-log₂ (x - 1) = 1 3) log4(x-1) +log4(x + 2) = 1
The solution(s) of the equation 22* – 2* = 12 is (are): A) x = log2(4) and x = - log2(3). B) x = log2(4). C) x = 4. D) x = log2(12). x = log2(12) and x = log2(13). E) %3D A) в) c) O D) O E)

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The principle value of (1 + i)¹*¹ is a) (1+i) exp i +-log 2 2 π 4 π i 4 2 b) (1+i) exp i c) (1-1) exp(-+-log 2) 4 2 -log 2 d) (1+i)exp(+11og2) 4