The principal part for x>0 xo a) x 5/6 +0 (x²³/6) b) 5x e) 25/6+4x c) 4x d) 25/6 11 how I solved it but I'm not sure (2³ +26) 6 + 4x ⇒ 25/6 (1 + x) 11/6 +4x +4a since 2516+! the smallest value right?

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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So the part where I’m confused in is it right to assume then when x->0+ we take the smallest exponent but in that case could you tell me if my computations are correct please
The principal part for x-ot of f(x)=√x² + x6 + 4x (with respect to y(x) = x) is:
a) 25/6+0(x³16)
how I solved it but I'm not sure
b) 5x
e) 2516 + 4x
c) 42
d) 2516
(25 +26) 16
+ 4x ⇒ x5/6 (1 + 1x) +4₂
11/6
+4a since 2
bot we
2516+1x
the smallest value right? so its d?
take
Transcribed Image Text:The principal part for x-ot of f(x)=√x² + x6 + 4x (with respect to y(x) = x) is: a) 25/6+0(x³16) how I solved it but I'm not sure b) 5x e) 2516 + 4x c) 42 d) 2516 (25 +26) 16 + 4x ⇒ x5/6 (1 + 1x) +4₂ 11/6 +4a since 2 bot we 2516+1x the smallest value right? so its d? take
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