The principal P is borrowed at a simple interest rater for a period of time t. Find the loan's future value A, or the total amount due at time t. P=$6000, r=4.5%, t = 4 months The loan's future value is $. (Do not round until the final answer. Then round to the nearest cent as needed.)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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The problem presented involves calculating the future value of a loan using simple interest. Here's a transcription of the text:

---

The principal \( P \) is borrowed at a simple interest rate \( r \) for a period of time \( t \). Find the loan’s future value \( A \), or the total amount due at time \( t \).

\( P = \$6000, \, r = 4.5\%, \, t = 4 \) months

---

The loan’s future value is \( \$ \_\_\_\_ \)

(Do not round until the final answer. Then round to the nearest cent as needed.)

---

To calculate the future value \( A \) using simple interest, we use the formula:

\[ 
A = P(1 + rt) 
\]

Here, the interest rate should be converted to a decimal and the time should be in years:

- \( r = 0.045 \) (4.5% as a decimal)
- \( t = \frac{4}{12} \) (4 months as a fraction of a year)

Calculate:

\[
A = 6000 \times (1 + 0.045 \times \frac{4}{12})
\]

This provides the total amount due at the end of the loan period.
Transcribed Image Text:The problem presented involves calculating the future value of a loan using simple interest. Here's a transcription of the text: --- The principal \( P \) is borrowed at a simple interest rate \( r \) for a period of time \( t \). Find the loan’s future value \( A \), or the total amount due at time \( t \). \( P = \$6000, \, r = 4.5\%, \, t = 4 \) months --- The loan’s future value is \( \$ \_\_\_\_ \) (Do not round until the final answer. Then round to the nearest cent as needed.) --- To calculate the future value \( A \) using simple interest, we use the formula: \[ A = P(1 + rt) \] Here, the interest rate should be converted to a decimal and the time should be in years: - \( r = 0.045 \) (4.5% as a decimal) - \( t = \frac{4}{12} \) (4 months as a fraction of a year) Calculate: \[ A = 6000 \times (1 + 0.045 \times \frac{4}{12}) \] This provides the total amount due at the end of the loan period.
Expert Solution
Step 1

Given  the principal amount P=$6000Interest rate r =4.5%=4.5100=0.045Time t=4 months          t= 412 year         t=13 year

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