The price-earnings (PE) ratios of a sample of stocks have a mean value of 13.75 and a standard deviation of 2.3. If the PE ratios have a bell shaped distribution, use the 68.2-95.4-99.7 Rule to estimate the percentage of PE ratios that fall between: A. 9.15 and 18.35. Percentage = % B. 6.85 and 20.65. Percentage = % C. 11.45 and 16.05. Percentage =

The price-earnings (PE) ratios of a sample of stocks have a mean value of 13.75 and a standard deviation of 2.3. If the PE ratios have a bell shaped distribution, use the 68.2-95.4-99.7 Rule to estimate the percentage of PE ratios that fall between: A. 9.15 and 18.35. Percentage = % B. 6.85 and 20.65. Percentage = % C. 11.45 and 16.05. Percentage =

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The price-earnings (PE) ratios of a sample of stocks have a mean value of 12.75 and a standard deviation of 2.8. If the PE ratios have a bell shaped distribution, what percentage of PE ratios that fall between: A. 9.95 and 15.55. Percentage = %B. 7.15 and 18.35. Percentage = %C. 4.35 and 21.15. Percentage = %
Suppose the durations of human pregnancies follow a mound-shaped distribution with a mean of 266 days and a standard deviation of 18 days. a. Approximately what percentage of human pregnancies last between 248 and 284 days? b. Between what two values will the durations of 95% of all human pregnancies fall? Answer in days
Is a measure of 29 inches "far away" from a mean of 19 inches? Suppose the data come from a sample whose standard deviation is 2 inches. A. How many standard deviation is 29 inches from 19 inches? b. Is 29 inches far away from a mean of 19 inches? c. Suppose the standard deviation of the underlying data is 7 inches. Is 29 inches far away from a mean of 19 inches?
Suppose that the antenna lengths of woodlice are approximately normally distributed with a mean of 0.22 inches and a standard deviation of 0.05 inches. What proportion of woodlice have antenna lengths that are at most 0.18 inches? Round your answer to at least four decimal places.
Suppose that the weight of male babies less than 2 months old is normally distributed with mean 11.5 pounds and standard deviation 2.7 pounds. What proportion of babies weigh less than 9.20 pounds?Write only a number as your answer. Round to 4 decimal places (for example 0.0048). Do not write as a percentage.
Human body temperatures for healthy individuals have approximately a normal distribution with mean 98.25 °F and standard deviation .75 °F. (The past accepted value of 98.6 Fahrenheit was obtained by converting the Celsius value of 370, which is correct to the nearest integer.) a. Find the 90th percentile of the distribution. b. Find the 5th percentile of the distribution. c. What temperature separates the coolest 25% from the others?
Please answer the following: You can Thank you. Adult IQ scores can be modeled using a normal model with mean 100 and a standadrd deviation of 15. a. Find the prportion of IQ scores that are less than 115. b. Find the proportion of IQ scores that are greater than 131.5. c. Find the proportion of IQ scores between 90 and 110. d. Find the proportion of IQ scores that are betewwn 110 and 120. e. Find the IQ score above which there are 10% of the scores. f. Find the IQ score below which there are 20% of the scores.
first picture is the background information
A set of final examination grades in an introductory statistics course was found to be normally distributed with a mean of 73 and a standard deviation of 8. Calculate: a.the percentage of students scored between 75 and 90 ( using Rstudio) b.the test score higher than what grade if only 5% of the students taking the test (manually and using R studio)
Q) The RATES of a SWEET BOX follows a normal distribution with a mean of $2.20 and a standard deviation of $0.20. Find the RATE for which 10.23% of sweet boxes are exceeded. Round your answer to nearest cent (hundredth) if necessary.
In 2011, the mean property crime rate (per 100,000 people) for 10 northeastern regions of a certain country was 2367. The standard deviation was 394. Assume the distribution of crime rates is unimodal and symmetric. What percentage of northeastern regions would you expect to have property crime rates between 1973 and 2761.