The pressure drop across a perforated-pipe distributor for turbulent flow conditions is given using the following correlation: 4 fL V? - 2K P AP = 3D Net pressure drop over the length of the distributor (N/m2) Pipe length (m) Diameter (m) Fanning friction factor (dimensionless) Distributor inlet velocity (m/s) Constant (dimensionless) Density in kg/m3 ere: ДР %3 D %3D f V; K %3D Demonstrate that the two sides of the above equation are dimensionally consistent. IL || || || || ||
The pressure drop across a perforated-pipe distributor for turbulent flow conditions is given using the following correlation: 4 fL V? - 2K P AP = 3D Net pressure drop over the length of the distributor (N/m2) Pipe length (m) Diameter (m) Fanning friction factor (dimensionless) Distributor inlet velocity (m/s) Constant (dimensionless) Density in kg/m3 ere: ДР %3 D %3D f V; K %3D Demonstrate that the two sides of the above equation are dimensionally consistent. IL || || || || ||
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:The pressure drop across a perforated-pipe distributor for turbulent flow
conditions is given using the following correlation:
4 fL
- 2K
3D
ДР —
-
2
Net pressure drop over the length of the distributor (N/m2)
Pipe length (m)
Diameter (m)
Fanning friction factor (dimensionless)
Distributor inlet velocity (m/s)
Constant (dimensionless)
Density in kg/m3
ere:
ΔΡ-
L
%D
%3D
f
%D
V;
K
%3D
Demonstrate that the two sides of the above equation are dimensionally
consistent.
I| || ||
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