The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that HF is a weak acid. acids: 2.3 mol of KOH is added to 1.0 L of a 1.4M HF solution. bases: other: acids: 0.07 mol of NaOH is added to 1.0 L of a solution that is 0.4M in both HF and KF. ☐ other: ☐ bases: 0,0....

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Chapter17: Acid-base(proton Transfer) Reactions
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The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at
equilibrium. You can leave out water itself.
Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the
formulas of the species that will act as neither acids nor bases in the 'other' row.
You will find it useful to keep in mind that HF is a weak acid.
2.3 mol of KOH is added to
1.0 L of a 1.4M HF
solution.
0.07 mol of NaOH is added
to 1.0 L of a solution that is
0.4M in both HF and KF.
☐ ☐
U
acids: ☐
bases: ☐
other: ☐
acids: ☐
bases: ☐
other: ☐
☐ ☐
×
⑤
Transcribed Image Text:The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that HF is a weak acid. 2.3 mol of KOH is added to 1.0 L of a 1.4M HF solution. 0.07 mol of NaOH is added to 1.0 L of a solution that is 0.4M in both HF and KF. ☐ ☐ U acids: ☐ bases: ☐ other: ☐ acids: ☐ bases: ☐ other: ☐ ☐ ☐ × ⑤
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