The power W dissipated in a resistor is proportional to the square of the voltage V. That is, W = rv² where r is a constant. If r 3, and V can be assumed (to a very good approximation) to be a normal random variable with mean μ = 6 and standard deviation σ = 1, find a. E[W] b. P{W > 120}

Q: Let X be a uniform (0,1) ran a. Find the CDF of Y. b. Find the PDF of Y. c. Find EY

A: It is given that  X follows Unif(0, 1) random variable.

Q: Find the z-score corresponding to a score of X = 50. μ= 60 and σ= 5 μ= 45 and σ=5 μ= 40 and σ= 5…

A: The formula for z-score is, z=X-μσ In the formula, X is the individual score, μ is the mean and σ is…

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Q: 1. Let Y1,..., Y, be a random sample from a normal distribution with mean u and variance 4. (a) Give…

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A: From the figure we can see, P.d.f of X  is given by, f(x)= 1/2 ,.        0<X<t

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Q: The standard deviation of the y(t)=3 sin(20rtt) is: 1.0606. O 2.1213. O 1.6062 O 2.2123.

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A: Note that this is a right-tailed test as the direction of alternative hypothesis is ">". And, the…

Q: Find the z-score corresponding to a score of X = 30 for each of the following: µ =50 and σ = 20 µ…

A: The formula for finding the z score is shown below:

Q: 5) Let Z be a normal variable with parameter µ = 500 and o = 30. Determine P(Z e [470, 560)

A: Consider a random variable Z which is

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A: The p.d.f is,  f(x)=65*(x2+x)  ,   0≤x≤1 a)  E(x)= ∫01x*f(x)dx     =∫01x*65*(x2+x)dx…

Q: Let X be the hardness measurement of a certain type of iron. A random sample of size n=40 is taken…

A: Here, n=40, x=172.3, and s2=100.

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A: Y is an exponential random variable with mean β . Therefore, the PDF of Y is:Result:∫eaxdx=eaxa

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Q: X is normal distributed with mean and standard deviation σ. What is P(X < µ)?

A: Provided information: Mean = μ Standard deviation = σ

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Q: Kindly answer it

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A: Given the Sample Variance of x1 , x2 , x3 , x4, --- , xn ∈ R  σ^2= 1n - 1 ∑i=1n (xi - x)2 where, x :…

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