The power of AM modulated signal is given by: Select one: O a. A² (m²(t)) O b. 4+ (m² (t)) Oc (m²(t)) O d. 4 + 4 (m² (t)) • If the message signal to be modulated according to DSB-SC method is as following: m(t)=0.5cos(21800t)-0.5cos(2111200t) Where the carrier signal has an amplitude A=1 and a frequency f=5KHz. Deduce the modulated signal x,(t) Select one: O a. xc(t)=0.25cos(205600t) +0.25cos(2114000t) +0.25cos(2016000t) +0.25cos(203800t) O b. x(t)=0.25cos(205600t) +0.25cos(2114000t)-0.25cos(2016000t)-0.25cos(2013800t) Oc. x(t)=cos(2115800t)+cos(24200t)-cos(216200t)-cos(2113800t) O d. xe(t)=0.25cos(2115800t) +0.25cos(2114200t)-0.25cos(216200t)-0.25cos(203800t)

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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15
nd
out of
question
m 16
ed
out of
question
The power of AM modulated signal is given by:
Select one:
O a A² (m² (t))
O b.
Oc
(m²(t))
O d. 4 + 4 (m² (t))
4+ (m² (t))
• If the message signal to be modulated according to DSB-SC method is as following:
m(t)=0.5cos(21800t)-0.5cos(211200t)
Where the carrier signal has an amplitude A=1 and a frequency f=5KHz.
Deduce the modulated signal xc(t)
Select one:
O a. xc(t)=0.25cos(215600t) +0.25cos(214000t) +0.25cos(216000t) +0.25cos(203800t)
O b. x(t)=0.25cos(215600t)
+0.25cos(274000t)-0.25cos(216000t)-0.25cos(203800t)
Oc xe(t)=cos(2715800t)+cos(24200t)-cos(216200t)-cos(2113800t)
O d. xe(t)=0.25cos(215800t) +0.25cos(214200t)-0.25cos(2116200t)-0.25cos(2113800t)
+
Transcribed Image Text:15 nd out of question m 16 ed out of question The power of AM modulated signal is given by: Select one: O a A² (m² (t)) O b. Oc (m²(t)) O d. 4 + 4 (m² (t)) 4+ (m² (t)) • If the message signal to be modulated according to DSB-SC method is as following: m(t)=0.5cos(21800t)-0.5cos(211200t) Where the carrier signal has an amplitude A=1 and a frequency f=5KHz. Deduce the modulated signal xc(t) Select one: O a. xc(t)=0.25cos(215600t) +0.25cos(214000t) +0.25cos(216000t) +0.25cos(203800t) O b. x(t)=0.25cos(215600t) +0.25cos(274000t)-0.25cos(216000t)-0.25cos(203800t) Oc xe(t)=cos(2715800t)+cos(24200t)-cos(216200t)-cos(2113800t) O d. xe(t)=0.25cos(215800t) +0.25cos(214200t)-0.25cos(2116200t)-0.25cos(2113800t) +
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