The power of a red laser (A = 630 nm) is 4.00 watts (abbreviated W, where 1W = 1 J/s). How many photons per second does the laser emit? photon/s
The power of a red laser (A = 630 nm) is 4.00 watts (abbreviated W, where 1W = 1 J/s). How many photons per second does the laser emit? photon/s
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Problem Statement:**
The power of a red laser (\(\lambda = 630 \, \text{nm}\)) is 4.00 watts (abbreviated W, where 1 W = 1 J/s). How many photons per second does the laser emit?
**Answer:**
[_______] photons/s
---
**Explanation:**
1. **Variables**:
- Wavelength (\(\lambda\)) = 630 nm
- Power (P) = 4.00 watts
2. **Formula**:
- **Energy of a Photon**: \(E = \frac{hc}{\lambda}\)
- \(h\) = Planck’s constant (\(6.626 \times 10^{-34} \, \text{Js}\))
- \(c\) = Speed of light (\(3.00 \times 10^{8} \, \text{m/s}\))
- \(\lambda = 630 \times 10^{-9} \, \text{m}\) (convert nm to m)
3. **Photons Per Second**:
- Calculate total energy output per second (\(P\)) and divide by the energy per photon to find photons per second.
This exercise requires students to apply physics concepts to determine the number of photons emitted by a laser, using power and wavelength data.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc31825ca-e532-4346-8c67-c6f0bc8ad95c%2F82250b95-e9f1-4c08-b107-a2c4b744f814%2Fyyb2lsg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
The power of a red laser (\(\lambda = 630 \, \text{nm}\)) is 4.00 watts (abbreviated W, where 1 W = 1 J/s). How many photons per second does the laser emit?
**Answer:**
[_______] photons/s
---
**Explanation:**
1. **Variables**:
- Wavelength (\(\lambda\)) = 630 nm
- Power (P) = 4.00 watts
2. **Formula**:
- **Energy of a Photon**: \(E = \frac{hc}{\lambda}\)
- \(h\) = Planck’s constant (\(6.626 \times 10^{-34} \, \text{Js}\))
- \(c\) = Speed of light (\(3.00 \times 10^{8} \, \text{m/s}\))
- \(\lambda = 630 \times 10^{-9} \, \text{m}\) (convert nm to m)
3. **Photons Per Second**:
- Calculate total energy output per second (\(P\)) and divide by the energy per photon to find photons per second.
This exercise requires students to apply physics concepts to determine the number of photons emitted by a laser, using power and wavelength data.
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