The potential energy at which neutralization occurs for the atoms X and Y in a diatomic salt corresponds to the ions X and Y being 0.55 nm apart. What is the value in kJ/mol of the change in internal energy required for this to occur? Hint: Multiply the negative of potential energy in kJ for a pair of charges +e, -e, separated by r = 0.55 nm, by Avogadro's number (per mole). The result is positive. a. 351 kJ/mol O b. 217 kJ/mol O c. 277 kJ/mol d. 252 kJ/mol e. 200 kJ/mol
The potential energy at which neutralization occurs for the atoms X and Y in a diatomic salt corresponds to the ions X and Y being 0.55 nm apart. What is the value in kJ/mol of the change in internal energy required for this to occur? Hint: Multiply the negative of potential energy in kJ for a pair of charges +e, -e, separated by r = 0.55 nm, by Avogadro's number (per mole). The result is positive. a. 351 kJ/mol O b. 217 kJ/mol O c. 277 kJ/mol d. 252 kJ/mol e. 200 kJ/mol
College Physics
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Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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![The potential energy at which neutralization occurs for the atoms X and Y in a
diatomic salt corresponds to the ions X and Y being 0.55 nm apart. What is
the value in kJ/mol of the change in internal energy required for this to occur?
Hint: Multiply the negative of potential energy in kJ for a pair of charges +e, -e,
separated by r = 0.55 nm, by Avogadro's number (per mole). The result is
positive.
a. 351 kJ/mol
b. 217 kJ/mol
c. 277 kJ/mol
d. 252 kJ/mol
O e. 200 kJ/mol](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc7fe5a73-45e4-4166-8ba1-50e355550dfc%2Fc5d6cfc3-fd79-4a7c-b078-4d63a153a710%2Ft2q9dbq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The potential energy at which neutralization occurs for the atoms X and Y in a
diatomic salt corresponds to the ions X and Y being 0.55 nm apart. What is
the value in kJ/mol of the change in internal energy required for this to occur?
Hint: Multiply the negative of potential energy in kJ for a pair of charges +e, -e,
separated by r = 0.55 nm, by Avogadro's number (per mole). The result is
positive.
a. 351 kJ/mol
b. 217 kJ/mol
c. 277 kJ/mol
d. 252 kJ/mol
O e. 200 kJ/mol
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