The position vector of a particle r(t) = ti + 7 In j+k. Find the acceleration 5 +t vector at t = 1 7 a(1) = 20i - 36j - 14k a(1) = 20i +j + 14k %3D a(1) = 20i + j - 14k %3D 7 a(1) = 20i + 6j + 14k

Q: Find the position vector for a particle with acceleration, initial velocity, and initial position…

A: As per given by the question, there are given: a→t=6t, 5sint, cos6tv→0=4, 3, 5r→0=3, -4, -4 Now, For…

Q: Q3: A particle traveling in a straight line is located at the point (1,-1,2) and has speed 2 at time…

A: Solution :-

Q: Consider the following graph. 6- (4, 4) (4, 4) (1, 2) 2 | (3. 2 3 5 2. 3. (1, 2) 3 4 5 6 -1- 5- (a)…

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Q: YouTrylt 2 Suppose that the acceleration of a particle is given by al =2 cos( 2/i +12sin(2/) i +2A…

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Q: The position vector of a particle is r(t). Find the requested vector. The acceleration at t = for…

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Q: Find the components of the vectors. (a) (1,5) (4,1)

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Q: The graph of the vector function r (t) = 2i + t²j+ tk is

A: Given function is r^t=2i^+t2j^+tk^. Plot the graph of the vector function. Choose some values for t…

Q: Find a vector perpendicular to each of the given vector a = ßi +j+k ,b = 4i + aj – k. %3D |

A: Applying cross product we have

Q: Find the terminal point Q of the vector v = 7i-j+3k given the initial point is P(-2, 3, 5) О (5, 2,…

A: In this question we have to find the terminal point of Q.

Q: It is known that the acceleration vector for a particle is given by A(t) = 4j + 2tk. Determine the…

A: We need to determine vector equation of curve traced.

Q: find the scalar equations of two planes which intersect along r=(3,2,-1) +t(1,-2,1). possible…

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Q: (15) Let u Then the angle (measured in radians) between these two vectors is equal to (b) (e) (d) 등…

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Q: At time t=0, a particle is located at the point (3,9,4). It travels in a straight line to the point…

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Q: The position vector of a particle is r(t) = (10t- 3t“)i + (6 – t)j + (6t² – 2t)k. Find the…

A: Given that rt=10t-3t4i+6-tj+6t2-2tkTo find the acceleration vector at t=2

Q: TA(t) = 2t i + (8t – 7) 3+ (5 – 4ť²) k TB(t) = (t? – 1) i+ (5t + 1) j+ (t – 6) k

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Q: If the position vector (with its tail at origin) of a moving particle be t2i -2t + (t² +2t)k. then…

A: Differentiating position vector with time we get velocity vector. And differentiation of a vector…

Q: 11 1. 0 2 00 2 Find det(A) (14) Let A 3 00-1 (a) 0 (b) 6 (c) -6 (d) -2 (e) 2

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Q: 4. Find the vector equation for a particle if A(t) = 6ti + 12t² j+ k, V(0) = 2i + 3j, and R(0) = 4k.

A: Given that At=6ti+12t2j+k,V0=2i+3j,r0=4k.