PROBLEM 2.17The position of an object as a function of time is given asx = 2.1t3 + t2 -4t + 3 where x is in meters and t is in seconds.19. What is the velocity of the object at t = 10.0 s?c. 946 md. 616 mа.936 mb.646 m20. At what time is the object at rest?0.654 sc. 0.454 sd. 0.754 sа.b.0.554 s21. What is the acceleration of the object at t = 0.50 s?с. 7.3 m/s2d. 9.3 m/s²6.3 m/s²8.3 m/s2а.b.

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Answered: The position of an object as a function…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Equation of Motion for a System of Particles Learning Goal: Consider the mass and pulley system shown. Mass m₁ = 32 kg and mass m₂ = 10 kg. The angle of the inclined plane is given, and the coefficient of kinetic friction between mass me and the inclined plane is μ = 0.12. Assume the pulleys are massless and frictionless. (Figure 1) Figure 1 of 1 98°F Sunny m₂ mi ▼ Pa Wh Exp V a Si Par If the Expr ▶ Vi
The end of the cable at A is pulled down with a constant speed. D V1 A Values for the figure are given in the following table. Note the figure may not be to scale. Variable Value m 3 V1 Using absolute dependent motion analysis of 2 particles, a. Determine the speed of the anvil, vB. b. Is the anvil going up or down? B
3) Two particles, A & B, move along parallel rectilinear paths. At t=0 the particles are directly opposite one another. Particle A moves according to SA = 12t² - 4t³ inches and particle B moves with a constant speed of 12 inches/ second. (a) Determine the relative position of A with respect to B at t = 1 second. (b) Determine the relative velocity of A with respect to B at t = 1 second. ANS. SA/B = -4 inches VA/B = 0 inches/sec
1. A chain of blocks is moving upward at 3 m/s. The tension in the cable connected to the top of the chain is To = 800 N. a. What is the acceleration of the chain of blocks? b. What is the tension in the cable connecting Block C and Block D? v = 3 m/s To = 800 N mA = 21 kg mB = 25 kg mc = 20 kg mp = 18 kg mg = 17 kg mp = 15 kg a = ? TCD = ?
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• 1. A particle position given by s(t) = 4 t2 - 32 t +36 with s in meters and t in seconds. At what position does the particle come to a # 1 %3D momentary stop to reverse its motion? par • 2. A particle moves in a straight line such that for a short time its velocity is defined by V = ( 4t3 + 3t2 seconds. Determine its position and acceleration when t = 3 s; 2t) ft/s, where t is in %3D %3D he when t = 0, S = 0 %3D e pa he particle for wertical disola reach the ground tance that the paticle travel haght of the paratle, he t lury paricle when the bonzonl distence i 70 m dislmce whn the hayht uf the paricle is %23
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