The position of a particle changes from ĩ1 = (2.02 + 3.03) cm to 72 = (-4.0i + 3.0j) cm. What is the particle's displacement vector? Use cm units.
The position of a particle changes from ĩ1 = (2.02 + 3.03) cm to 72 = (-4.0i + 3.0j) cm. What is the particle's displacement vector? Use cm units.
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter1: Introduction And Vectors
Section: Chapter Questions
Problem 46P: Vector A has x and y components of 8.70 cm and 15.0 cm, respectively; vector B has x and y...
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Hi, can someone help me with this one please
![The position of a particle changes from ĩ1 = (2.02 + 3.03)
cm to 72 = (-4.0i + 3.0j) cm. What is the particle's
displacement vector? Use cm units.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1565eeb3-ae41-4180-a8ff-04b06f857e13%2F993a7b0a-85cb-41cc-8620-4ac6fbbf2d83%2F46xp5a_processed.png&w=3840&q=75)
Transcribed Image Text:The position of a particle changes from ĩ1 = (2.02 + 3.03)
cm to 72 = (-4.0i + 3.0j) cm. What is the particle's
displacement vector? Use cm units.
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