1. The position of a particle along a straight line is given by s = (1.5t³ – 13.5t2 + 22.5t), where t is inseconds. Determine the displacement and the total distance it travels during the 7-s time interval.2. A ball is thrown with an upward velocity of 6.5 m/s from the top of a 12-m high building. One secondlater another ball is thrown vertically from the ground with a velocity of 12 m/s. Determine the heightfrom the ground where the two balls pass each other.3. A ball is fired downwards into a medium with an initial speed of 26 m/s. If it experiences adeceleration of a = (-5.3t)m/s² where t is in seconds, determine the distance traveled before itstops.

s=1.5t3-13.5t2+22.5tv=dsdt=4.5t2-27t+22.5at t=1,5 velocity becomes zero or we can say particle…

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The position of a particle along a straight line is given by s = (1.5t³ – 13.5t2 + 22.5t), where t is in n seconds. Determine the displacement and the total distance it travels during the 7-s time interval.