The position of a moving particle in space is vgiven by r(t) = (- 76- 21) i + (108t° - 2890) j + (181 + 11) k t20. (i) Determine position , velocity , acceleration and speed of the particle at t=2. (ii) Find the vector equation of the straight line tangent to the curve at the point Q(- 82,26,173). () r(2)=(D.0.J) v (2) = (O.O.0) a (2) = (O.0.J) Speed = || v (2)|| = (ii) Equation of thangent line r (s) = (- 82,26,173)+( SE R
The position of a moving particle in space is vgiven by r(t) = (- 76- 21) i + (108t° - 2890) j + (181 + 11) k t20. (i) Determine position , velocity , acceleration and speed of the particle at t=2. (ii) Find the vector equation of the straight line tangent to the curve at the point Q(- 82,26,173). () r(2)=(D.0.J) v (2) = (O.O.0) a (2) = (O.0.J) Speed = || v (2)|| = (ii) Equation of thangent line r (s) = (- 82,26,173)+( SE R
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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CAN YOU SOLVE THE TWO PARTS
![The position of a moving particle in space is vgiven by
r(t) = (- 76– 21) i + (108t - 2890) į + (181 + 11) k
t20.
(i) Determine position , velocity , acceleration and speed of the particle at t=2.
(ii) Find the vector equation of the straight line tangent to the curve at the point
Q(- 82,26,173).
(1) r(2) =(].]·)
v (2) = (O.O.0)
a (2) = (O.0.J)
Speed = || v (2)|| =
(ii) Equation of thangent line r (s) = (- 82,26,173)+(
SE R](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F008f31aa-ffde-472d-81b9-49fb75f4a0c2%2Fb8688442-281c-4002-87d4-8e79fe1c0efa%2F7grtez_processed.png&w=3840&q=75)
Transcribed Image Text:The position of a moving particle in space is vgiven by
r(t) = (- 76– 21) i + (108t - 2890) į + (181 + 11) k
t20.
(i) Determine position , velocity , acceleration and speed of the particle at t=2.
(ii) Find the vector equation of the straight line tangent to the curve at the point
Q(- 82,26,173).
(1) r(2) =(].]·)
v (2) = (O.O.0)
a (2) = (O.0.J)
Speed = || v (2)|| =
(ii) Equation of thangent line r (s) = (- 82,26,173)+(
SE R
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