The position of a 2.75 X 10³-N raining helicopter under test is given by 7 = (0.020 m/s³)³ + (2.2 m/s)tj- (0.060 m/s²)rk. Find the net force on the helicopter at/= 5.0 s.

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The position of a 2.75 × 10³-N
training helicopter under test is given by 7 = (0.020 m/s³)³ +
(2.2 m/s) (0.060 m/s²)rk. Find the net force on the helicopter
at / = 5.0 s.
Transcribed Image Text:The position of a 2.75 × 10³-N training helicopter under test is given by 7 = (0.020 m/s³)³ + (2.2 m/s) (0.060 m/s²)rk. Find the net force on the helicopter at / = 5.0 s.
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