I have the answers below. I only need the solution. The portion of truss shown representsthe upper part of a power transmissionline tower. The 2.7 kN force is 60° fromthe vertical. For the given loading,determine all zero force members.a. Use the Method of Section to find the FEH = 2.9228 kN, CAnswers:FBC = 0.9878 kN, Tforces in members BC, EH and EJ;b. Use the Method of Joints to find theFEJ = 0.5841 kN, CFBD = 1.3171 kN, TFDE = 0.3576 kN, C%3Dforces in members BD and DE;1.60 m-2.21 m-B2.21 m-Al0.60 m0.60 mE2.7 kN1.20 m1.2 kNH0.60 m0.60 mK-2.97 m-1.2 kN1.20 mN1.2 kNM!0.60 m0.60 mR1.2 kN1.2 kNT

FH = Horizontal component of 2.7 KN forceFH = 2.7 sin(60) = 2.3383 KNFV = Vertical component of 2.7…

The portion of truss shown represents the upper part of a power transmission line tower. The 2.7 kN force is 60° from the vertical. For the given loading, determine all zero force members. a. Use the Method of Section to find the forces in members BC, EH and EJ; b. Use the Method of Joints to find the forces in members BD and DE;