The population of a town is growing according to the differential equation dy/dt =ky The growth constant, k, is equal to 0.11 year -1. The size of the population at the start of the year 2000 was 30 thousand. Since the population is growing exponentially, the population in year t is given by y=30e^0.11t Here, y is measured in thousa
The population of a town is growing according to the differential equation
dy/dt =ky
The growth constant, k, is equal to 0.11 year -1.
The size of the population at the start of the year 2000 was 30 thousand.
Since the population is growing exponentially, the population in year t is given by
y=30e^0.11t
Here, y is measured in thousands and t is measured in years since 2000.
- What is the population of the town at the start of the year 2006?
(Enter your answer correct to one decimal place.)
Population: ___ thousand.
- How many years does it take for the population to double?
(Enter your answer correct to two decimal places.)
Doubling time : ___ years.
- What will be the size of the population after three doubling times have passed? (That is, after three times the correct answer to part b have passed?)
(Enter your answer correct to one decimal place.)
Population after three doubling times : ___ thousand.
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
im confused on the last part:
What will be the size of the population after three doubling times have passed? (That is, after three times the correct answer to part b have passed?)
(Enter your answer correct to one decimal place.)
Population after three doubling times : thousand.
there was no answer given that is is a whole number?
by Bartleby Expert
