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The population of a small town as a function of the time, t, is given by the function P(t) = Poert where Po is the initial population at the time when we begin measuring, and r is the growth rate per year. Suppose that the population of Oil Patch, Oklahoma, was 5,784 in the 2000 census. In 2010 it had risen to 6,111. If we assume the growth rate was the same throughout the decade, then find the growth rate, r to the nearest tenth of a percent (Hint:

The population of a small town as a function of the time, t, is given by the function P(t) = Poert where Po is the initial population at the time when we begin measuring, and r is the growth rate per year. Suppose that the population of Oil Patch, Oklahoma, was 5,784 in the 2000 census. In 2010 it had risen to 6,111. If we assume the growth rate was the same throughout the decade, then find the growth rate, r to the nearest tenth of a percent (Hint:

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The population of a small town as a function of the time, t, is given by the function P(t) = Poert where Po is the initial population at the time when we begin measuring, and r is the growth rate per year. Suppose that the population of Oil Patch, Oklahoma, was 5,784 in the 2000 census. In 2010 it had risen to 6,111. If we assume the growth rate was the same throughout the decade, then find the growth rate, r to the nearest tenth of a percent (Hint: Use your graphing calculator and find the point of intersection).
Transcribed Image Text:The population of a small town as a function of the time, t, is given by the function P(t) = Poert where Po is the initial population at the time when we begin measuring, and r is the growth rate per year. Suppose that the population of Oil Patch, Oklahoma, was 5,784 in the 2000 census. In 2010 it had risen to 6,111. If we assume the growth rate was the same throughout the decade, then find the growth rate, r to the nearest tenth of a percent (Hint: Use your graphing calculator and find the point of intersection).
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