The population mean and standard deviation are given below. Find the required probability and determine whether the given sample mean would be considered unusual.For a sample of n = 61, find the probability of a sample mean being less than 22.6 if µ = 23 and o= 1.15.Click the icon to view page 1 of the standard normal table.Click the icon to view page 2 of the standard normal table.For a sample of n = 61, the probability of a sample mean being less than 22.6 if µ = 23 and o=1.15 is(Round to four decimal places as needed.)Standard Normal Table (Page 1)AreaZZ.09.08.07.06.05.04.03.02.01-3.4 .0002 .0003 .0003 .0003 .0003 0003 .0003 .0003 .0003-3.3 .0003 .0004 .0004 .0004 .0004 0004 .0004 .0005 .0005-3.2 .0005 .0005 .0005 .0006 .0006 0006 .0006 .0006 .0007-3.1 .0007 .0007 .0008 .0008 .0008 0008 .0009 .0009 .0009-3.0 .0010 .0010 .0011 .0011 .0011 0012 .0012 .0013 .0013-2.9 .0014 .0014 .0015 .0015 .0016 .0016 .0017 .0018 .0018-2.8 .0019 .0020 .0021 .0021 .0022 0023 .0023 .0024 .0025-2.7 .0026 .0027 .0028 .0029 .0030 .0031 .0032 .0033 .0034-2.6 .0036 .0037 .0038 .0039 .0040 0041 .0043 .0044 .0045-2.5 .0048 .0049 .0051 .0052 .0054 .0055 .0057 .0059 .0060-2.4 .0064 .0066 .0068 .0069 .0071 .0073 .0075 .0078 .0080-2.3 .0084 .0087 .0089 .0091 .0094 0096 .0099 .0102 .0104-2.2 .0110 0113 .0116 .0119 0122 0125 .0129 0132 .0136-2.1 .0143 .0146 .0150 .0154 .0158 0162 .0166 .0170 .0174-2.0 .0183 .0188 .0192 .0197 .0202 0207 .0212 .0217 .0222-1.9 .0233 .0239 .0244.0250 .0256 .0262 .0268 .0274 .0281-1.8 .0294 0301 .0307 .0314 0322 0329 .0336 .0344 .0351-1.7 .0367 .0375 .0384 .0392 .0401 0409 .0418 .0427 .0436-1.6 .0455 .0465 .0475 .0485 .0495 0505 .0516-1.5 .0559 .0571 .0582 .0594 .0606 0618 .0630-1.4 .0681 .0694 .0708 .0721 0735 0749 .0764-1.3 .0823 .0838 0853 .0869 .08850901.0526 .0537.0643 .06550778 .0793.0918 0934 .0951.00.0003.0005.0007.0010.0013.0019.00260035.0047.0062008201070139.0179022802870359.0446.0548.066808080968-X The population mean and standard deviation are given below. Find the required probability and determine whether the given sample mean would be considered unusual.For a sample of n = 61, find the probability of a sample mean being less than 22.6 if µ = 23 and o= 1.15.Click the icon to view page 1 of the standard normal table.Click the icon to view page 2 of the standard normal table.For a sample of n = 61, the probability of a sample mean being less than 22.6 if µ = 23 and o = 1.15 is(Round to four decimal places as needed.)Standard Normal Table (Page 2)Z0.00.10.20.30.40.50.60.70.80.91.01.11.21.31.41.51.61.71.81.92.02.1Area0ZZ.00.01.02.03.04.05.06.07.08.09.5000 .5040 5080 .5120 5160 5199 .5239 5279 .5319 .5359.5398 .5438 5478 .5517 .5557 .5596 .5636 .5675 .5714 .5753.5793 5832 .5871 .5910 .5948 5987 .6026 .6064.6103.6141.6179 .6217 .6255 .6293 .6331 .6368 .6406 .6443 .6480 .6517.6554 .6591 .6628 .6664 .6700 .6736 .6772 .6808 .6844 .6879.6915 .6950 .6985 .7019 .7054 .7088 .7123 .7157 .7190 .7224.7257 7291 .7324 .7357 .7389 .7422 7454 .7486 .7517 .7549.7580 .7611 .7642 .7673 .7704 .7734 .7764 .7794 .7823 .7852.7881 .7910 .7939 .7967 .7995 .8023 8051 .8078 .8106 8133.8159 .8186 .8212 8238 .8264 .8289 .8315 .8340 .8365 .83898413 .8438 .8461 .8485 8508 .8531 .8554 .8577 8599 .8621.8643 .8665 .8686 8708 .8729 .8749 .8770 .8790 88108849 8869 .8888 .8907 .8925 .8944 .8962 .8980 8997.9032 .9049 .9066 .9082 .9099 9115 .9131 .9147 .9162.9192 .9207 .9222 .9236 .9251 .9265 .9279 .9292 .9306.9332 .9345 .9357 .9370 .9382 .9394 .9406 .9418 .9429.9452 .9463 .9474 .9484 .9495 .9505 .9515 .9525 .9535.9554 .9564 .9573 .9582 .9591 .9599 .9608 .9616 .9625.9641 .9649 .9656 .9664 .9671 .9678 .9686.9693 .9699.9750 .9756 .9761.9772 .9778 .9783 .9788 .9793 .9798 .9803 .9808 .9812.9821 .9826 .9830 .9834 .9838 .9842 .9846 .9850 .98548830.9015.9177.93199441.9545.9633.9706.9713 .9719 .9726 .9732 .9738 .9744.9767.9817.9857IX

Given,mean(μ)=23standard deviation (σ)=1.15sample size(n)=61

The population mean and standard deviation are given below. Find the required probability and determine whether the given sample mean would be considered unusual. For a sample of n = 61, find the probability of a sample mean being less than 22.6 if µ = 23 and a = 1.15. Click the icon to view page 1 of the standard normal table. Click the icon to view page 2 of the standard normal table. For a sample of n=61, the probability of a sample mean being less than 22.6 if µ = 23 and o=1.15 is. (Round to four decimal places as needed.) Standard Normal Table (Page 1) Area D Z 05 .02 .01 .0003 .09 .08 .07 .06 .04 .03 -3.4 0002 0003 0003 .0003 0003 0003 .0003 0003 -3.3 0003 0004 0004 0004 0004 0004 .0004 0005 .0005 -3.2 .0005 0005 0005 0006 0006 0006 .0006 0006 0007 -3.1 0007 0007 0008 .0008 0008 0008 0009 .0009 0009 <-3.0 0010 0010 0011 0011 0011 0012 .0012 .0013 .0013 -2.9 0014 0014 0015 .0015 0016 0016 .0017 0018 0018 -2.8 0019 0020 0021 0021 0022 0023 0023 0024 0025 -2.7 0026 0027 0028 0029 0030 0031 0032 0033 0034 -2.6 .0036 0037 0038 0039 0040 0041 0043 0044 0045 -2.5 0048 0049 0051 0052 .0054 0055 .0057 .0059 0060 -2.4 0064 0066 0068 .0069 0071 0073 .0075 .0078 0080 -2.3 0084 0087 0089 .0091 0094 0096 0099 0102 0104 -2.2 0110 0113 0116 0119 0122 0125 0129 0132 0136 -2.1 0143 0146 0150 0154 0158 0162 0166 0170 0174 -2.0 0183 0188 0192 0197 0202 0207 0212 0217 0222 -1.9 0233 0239 0244 0250 0256 0262 0268 0274 0281 -1.8 0294 0301 0307 0314 0322 0329 0336 0344 0351 -1.7 0367 0375 0384 0392 0401 0409 0418 0427 0436 16 0455 0465 0475 0485 0495 0505 0516 0526 0537 .00 0003 0005 0007 0010 0013 0019 0026 0035 0047 0062 0082 0107 0139 0179 0228 0287 0359 0446 0548 - X

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...