The population in an African preserve is estimated to at 600 lions. Thegrowth rate based on the last two years is about 3% per year. If trepresents time in years after this year, which functions best models thissituation?= 600(1.03)*а.b. y = 600 + 1.03tc. Y = 600(0.03)'X d. y = 600 + 0.03ty = 600(1.03)*-1е.

Answered: The population in an African preserve…

College Algebra

1st Edition

ISBN:9781938168383

Author:Jay Abramson

Publisher:Jay Abramson

Chapter6: Exponential And Logarithmic Functions

Section6.8: Fitting Exponential Models To Data

Problem 3TI: Table 6 shows the population, in thousands, of harbor seals in the Wadden Sea over the years 1997 to...

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Table 2 shows a recent graduate’s credit card balance each month after graduation. a. Use exponential regression to fit a model to these data. b. If spending continues at this rate, what will the graduate’s credit card debt be one year after graduating?
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Gold Tracker monitors the price of precious metals and has daily data on prices and sales of gold for the past several years. They estimated the following relationship (250 observations): Q=4,000-0.01P+1.5I-1.25X+2.0S R^2=.96 Q=daily sale of gold in ounces, P=price of gold per ounce, I= most recent inflation report (in percent), X= index of exchange rate, S is market price of silver per ounce. Standard errors are 857 for 4,000; 0.002 for 0.01P; 0.65 for 1.5I; 0.44 for 1.25X; 0.48 for 2.0S A. Evaluate the results of this regression. B. Recently, the price of gold has been $380 per ounce, inflation 0.2%, dollar trading at 99.7 on index, silver is $4.75 per ounce. What quantity of gold will trade on a daily basis? C. Are gold and silver substitutes or compliments?
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On the basis of quartely sales (in lakhs) of a certain commodity for the years 2003-2004 following calculations were made: Y = 20 +0.5 r with origin at 1st quarter of 2003. %3D Are = time unit = one quarter and Y= quarterly sales (in $) Seasonal variations. Quarter I ii iii iv Seasonal index 80 90 120 110 Estimate the quarterly sale for the year 1990 using multiplicative model.
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You plan to invest in an account which pays 4% compounded continuously. If the investment period is for 11 years, then A(P) = Pe 0.04 · 11 = Pe0.44 gives the total balance of P dollars. %3D Find a formula for A'(P). Find and interpret A'(8000). Compare the approximation to the actual change. a. b. C. a. A (P) = Εi. b. A'(8000) = Interpret A'(8000) = 1.55 O A. The future value of a 11 year investment of $8001 will be $ more than the future value of a 11 year investment of $8000. O B. The future value of 11 year investment of $8000 at 5% will be $ more than the future value of a 11 year investment of $4000 at 4%. O C. The future value of a 12 year investment of $8001 will be $ more than the future value of a 12 year investment of $8000. O D. The future value of a 12 year investment of $8000 will be $ more than the future value of a 12 year investment of $8000.

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