The polynomial of degree 5, P(x), has leading coefficient 1, has roots of multiplicity 2 at = 1 and a = 0, and a root of multiplicity 1 at a = -2. Find a possible formula for P(x). P(x) x²(x-1)²(x+2)
The polynomial of degree 5, P(x), has leading coefficient 1, has roots of multiplicity 2 at = 1 and a = 0, and a root of multiplicity 1 at a = -2. Find a possible formula for P(x). P(x) x²(x-1)²(x+2)
Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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![The polynomial of degree 5, \( P(x) \), has leading coefficient 1, has roots of multiplicity 2 at \( x = 1 \) and \( x = 0 \), and a root of multiplicity 1 at \( x = -2 \).
Find a possible formula for \( P(x) \).
\[ P(x) = x^2 (x - 1)^2 (x + 2) \]
**Question Help:** ▶ Video](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdc702ff9-d3e6-4e4b-abbc-7bc2699ae04d%2F4a76f845-0a1d-48e5-bd7f-75b71f1a2d93%2F2spfka_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The polynomial of degree 5, \( P(x) \), has leading coefficient 1, has roots of multiplicity 2 at \( x = 1 \) and \( x = 0 \), and a root of multiplicity 1 at \( x = -2 \).
Find a possible formula for \( P(x) \).
\[ P(x) = x^2 (x - 1)^2 (x + 2) \]
**Question Help:** ▶ Video
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