The pole in the figure is a a 90° bend in a power line and is therefore subjected to more shear force than poles in straight parts of the line. The tension in the two wires at the top of the pole is 3.5 × 104 N, and both wires are at an angle of 80° with respect to the pole. The pole is 15 m tall, has an 16 cm diameter and can be considered to have half the strength of hardwood (hardwood has a Young's modulus of 1.5×1010 N/m2 and a shear modulus of 1×010 N/m2).     a)  First ignore the guy wire (Tgw). Calculate the compression of the pole, in millimeters. b) Still ignoring the guy wire, Find how much it bends in mm to the right. c) Now find the tension in the guy wire used to keep the pole straight if it is attached to the top of the pole at an angle of 30° with the vertical in Newtons. (The guy wire must be in the opposite direction of the bend.)

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Chapter1: Units, Trigonometry. And Vectors
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 The pole in the figure is a a 90° bend in a power line and is therefore subjected to more shear force than poles in straight parts of the line. The tension in the two wires at the top of the pole is 3.5 × 104 N, and both wires are at an angle of 80° with respect to the pole. The pole is 15 m tall, has an 16 cm diameter and can be considered to have half the strength of hardwood (hardwood has a Young's modulus of 1.5×1010 N/m2 and a shear modulus of 1×010 N/m2).

 

 

a)  First ignore the guy wire (Tgw). Calculate the compression of the pole, in millimeters.

b) Still ignoring the guy wire, Find how much it bends in mm to the right.

c) Now find the tension in the guy wire used to keep the pole straight if it is attached to the top of the pole at an angle of 30° with the vertical in Newtons. (The guy wire must be in the opposite direction of the bend.) 

A
90°
Tgw
30°
80°
1il
Transcribed Image Text:A 90° Tgw 30° 80° 1il
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