The polarity of a bond is measured by the values of the partial charge (8+ and &-) created. u is the dipole moment measured in Debye (D) -30 ( 1D = 3.336 x 100 Cm) q is the partial charge on the atoms e is the charge of an electron in C (coulomb) ris the bond length in m (metre) %3D = qxexr(C m) Example. HF has a dipole moment of 1.83 D and a bond length of 92 pm (92x10-12m) Calculate the value of q q= ul (exr) = 0.41

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Chapter1: Chemical Foundations
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Please explain why the example has been solved like this and how we knew the  charge of electron

(1D = 3.336 x 100 Cm)
The polarity of a bond is measured by the values of the partial charge (8+ and &-) created,
u is the dipole moment measured in Debye (D)
%3D
H = xe xr (C m)
q is the partial charge on the atoms
e is the charge of an electron in C (coulomb)
ris the bond length in m (metre)
Example. HF has a dipole moment of 1.83 D and a bond length of 92 pm (92x10-12m)
Calculate the value of q
q(e xr) = 0.41
Transcribed Image Text:(1D = 3.336 x 100 Cm) The polarity of a bond is measured by the values of the partial charge (8+ and &-) created, u is the dipole moment measured in Debye (D) %3D H = xe xr (C m) q is the partial charge on the atoms e is the charge of an electron in C (coulomb) ris the bond length in m (metre) Example. HF has a dipole moment of 1.83 D and a bond length of 92 pm (92x10-12m) Calculate the value of q q(e xr) = 0.41
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