The points H, I, J and K all lie on the same line segment, in that order, such that the ratio of HI : IJ : JK is equal to 2 :1: 2. If HK = 25, find JK.

Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter7: Equations And Inequalities In Two Variables
Section7.4: Determining The Equation Of A Line
Problem 82PS
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**Problem Statement:**

The points H, I, J, and K all lie on the same line segment, in that order, such that the ratio of \( H I : I J : J K \) is equal to \( 2 : 1 : 2 \). If \( H K = 25 \), find \( J K \).

**Solution:**

1. **Understanding the Problem:**
    - We are given four points on a line segment: H, I, J, and K.
    - The ratio of the line segments \( H I \), \( I J \), and \( J K \) is 2:1:2.
    - The total length \( H K \) is 25 units.

2. **Approach:**
    - Let the lengths \( H I \), \( I J \), and \( J K \) be represented as \( 2x \), \( x \), and \( 2x \) respectively, based on the given ratio.

3. **Setting up the Equation:**
    - According to the problem, the total length \( H K = 2x + x + 2x = 5x \).
    - We are given that \( H K = 25 \).

4. **Solving for \( x \):**
    - \( 5x = 25 \)
    - \( x = 25 / 5 \)
    - \( x = 5 \)

5. **Finding \( J K \):**
    - The length \( J K = 2x = 2 \times 5 = 10 \).

**Final Answer:**
\( J K = 10 \)

This approach ensures that the given conditions are satisfied, and the lengths are proportional to the given ratio.
Transcribed Image Text:**Problem Statement:** The points H, I, J, and K all lie on the same line segment, in that order, such that the ratio of \( H I : I J : J K \) is equal to \( 2 : 1 : 2 \). If \( H K = 25 \), find \( J K \). **Solution:** 1. **Understanding the Problem:** - We are given four points on a line segment: H, I, J, and K. - The ratio of the line segments \( H I \), \( I J \), and \( J K \) is 2:1:2. - The total length \( H K \) is 25 units. 2. **Approach:** - Let the lengths \( H I \), \( I J \), and \( J K \) be represented as \( 2x \), \( x \), and \( 2x \) respectively, based on the given ratio. 3. **Setting up the Equation:** - According to the problem, the total length \( H K = 2x + x + 2x = 5x \). - We are given that \( H K = 25 \). 4. **Solving for \( x \):** - \( 5x = 25 \) - \( x = 25 / 5 \) - \( x = 5 \) 5. **Finding \( J K \):** - The length \( J K = 2x = 2 \times 5 = 10 \). **Final Answer:** \( J K = 10 \) This approach ensures that the given conditions are satisfied, and the lengths are proportional to the given ratio.
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