The points ​(-4​,-4​) and ​(3​,6​) are the endpoints of the diameter of a circle. Find the length of the radius of the circle.I can get the equation down tosqrt 149 now my text book says the next step is to evaluate the square root then divide by 2.... But this particular square root does not break down. please help

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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The points ​(-4​,-4​) and ​(3​,6​) are the endpoints of the diameter of a circle. Find the length of the radius of the circle.
I can get the equation down to
sqrt 149

now my text book says the next step is to evaluate the square root then divide by 2.... But this particular square root does not break down. please help

Expert Solution
Step 1

The distance between two points (x1,y1) and (x2,y2) is given by:

Given points are (x1,y1) = (-4​,-4​) and (x2,y2) = (3​,6​)

Plugging the values in the formula,

Hence the diameter of the circle is 12.2 units.

 

Therefore the radius is given by 12.2/2 = 6.1 units.

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