The point P(1, 0) lies on the curve y = sin( (1) 2 (a) If Q is the point (x, sin(¹77)), find the slope of the secant line PQ (correct to four decimal places) for the following values of x. (ii) 1.5 (iii) 1.4 (iv) 1.3 (v) 1.2 (vi) 1.1 17π (vii) 0.5 X

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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The point P(1, 0) lies on the curve y
(a) If Q is the point (x, sin(¹77)).
(1) 2
(ii) 1.5
(iii) 1.4
(iv) 1.3
(v) 1.2
(vi) 1.1
(vii) 0.5
= sin
in (¹777).
find the slope of the secant line PQ (correct to four decimal places) for the following values of x.
Transcribed Image Text:The point P(1, 0) lies on the curve y (a) If Q is the point (x, sin(¹77)). (1) 2 (ii) 1.5 (iii) 1.4 (iv) 1.3 (v) 1.2 (vi) 1.1 (vii) 0.5 = sin in (¹777). find the slope of the secant line PQ (correct to four decimal places) for the following values of x.
>
Section...
(ix) 0.7
(x) 0.8
(xi) 0.9
Need Help?
ATA
Do the slopes appear to be approaching a limit?
As x approaches 1, the slopes do not appear to be approaching any particular value O
Submit Answer
O
Read It
webassign.net
Viewing Saved Work Revert to Last Response
WE
G
(b) Use a graph of the curve to explain why the slopes of the secant lines in part (a) are not close to the slope of the tangent line at P.
We see that problems with estimation are caused by the frequent oscillations of the graph. The tangent is so steep at P that we need
to take x-values closer
to 1 in order to get accuräte estimates of it's slope.
(c) By choosing appropriate secant lines, estimate the slope of the tangent line at P. (Round your answer to two decimal places.)
A
+ 9
11₁
Transcribed Image Text:> Section... (ix) 0.7 (x) 0.8 (xi) 0.9 Need Help? ATA Do the slopes appear to be approaching a limit? As x approaches 1, the slopes do not appear to be approaching any particular value O Submit Answer O Read It webassign.net Viewing Saved Work Revert to Last Response WE G (b) Use a graph of the curve to explain why the slopes of the secant lines in part (a) are not close to the slope of the tangent line at P. We see that problems with estimation are caused by the frequent oscillations of the graph. The tangent is so steep at P that we need to take x-values closer to 1 in order to get accuräte estimates of it's slope. (c) By choosing appropriate secant lines, estimate the slope of the tangent line at P. (Round your answer to two decimal places.) A + 9 11₁
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