The point P lies in the curve with equatioh x = (4y – sin 2y)² Given that P has (x, y) coordinates (p,"), where p is a constant, (i) find the exact value of p. X=0. The tangent to the curve at P cuts the y-axis at point A. ii) Find the exact coordinate of A.

Q: (-14) + (–7)

A:

Q: b. N(0)

A: Given,  r→t=sint, t, cost                   ...1

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A:

Q: 5/14+1/6

A: 514+16=15+742

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A: We can find the value of x as below

Q: In the

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Q: -7 3. Find (3-4) 5) 1 1

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Q: 1. v₁ = (4, −2, 6, −4), V₂ = (6, −3, 9, −6)

A:

Q: 3(m – 5) + m

A: 3(m-5)+m=0 3m-15+m=0 add both side 15 we get 2m=15