The point charges in the figure below are located at the corners of an equilateral triangle 25.0 cm on a side, where q, = +19.0 µC and q, = -5.70 µc. (Assume that the +x-axis is directed to the right.) (a) Find the electric field at the location of g.. magnitude N/C direction • (counterclockwise from the +x-axis) (b) What is the force on q, given that q, = +1.50 nC? magnitude N direction • (counterclockwise from the +x-axis)

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The point charges in the figure below are located at the corners of an equilateral triangle 25.0 cm on a side, where q, = +19.0 µC and q.
= -5.70 µC. (Assume that the +x-axis is directed to the
right.)
la
(a) Find the electric field at the location of q..
magnitude
N/C
direction
° (counterclockwise from the +x-axis)
(b) What is the force on
given that
9a
= +1.50 nC?
magnitude
N
direction
(counterclockwise from the +x-axis)
Transcribed Image Text:The point charges in the figure below are located at the corners of an equilateral triangle 25.0 cm on a side, where q, = +19.0 µC and q. = -5.70 µC. (Assume that the +x-axis is directed to the right.) la (a) Find the electric field at the location of q.. magnitude N/C direction ° (counterclockwise from the +x-axis) (b) What is the force on given that 9a = +1.50 nC? magnitude N direction (counterclockwise from the +x-axis)
Expert Solution
Step 1

All the 3 given charges in the problem are located on the corners of an equilateral triangle, having a side length of 25 cm

Let r=25 cm=0.25 m

qb=19 μC=19×10-6 Cqc=-5.7 μC=-5.7×10-6 C

All these charges will produce an electric field around them, which is given by the following equation

E=kqr2k is a constant, k=9×109r is the distance between the charge and the point of field

Positive charges have their electric fields directed radially away, while negative charges have their fields radiated towards them.

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